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3 years ago

Can someone please help me with the first question?????? please

Social Studies

1 answer:

zalisa [80]3 years ago

3 0

Answer:

Ohio River Valley

Explanation:

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7 years ago the population was at 1720 and today only 950 of the birds are alive. Once the population drops below 150, the situa

Harrizon [31]

Answer:

This will happen in 28.79 years.

Explanation:

The population, after t years, is given by the following equation:

$P(t) = P_{0}(1 + r)^{t}$

In which $P_{0}$ is the initial population and r is the rate of change. If r is positive, the population increases. Otherwise, if r is negative, the population decreases.

7 years ago the population was at 1720 and today only 950 of the birds are alive.

This means that $P_{0} = 1720$ and $P(7) = 950$ . With this, we can find r. So

$P(t) = P_{0}(1 + r)^{t}$

$950 = 1720(1 + r)^{7}$

$(1+r)^{7} = \frac{950}{1720}$

$(1+r)^{7} = 0.5523$

To isolate 7, i apply the seventh root to both sides. so

$\sqrt[7]{(1+r)^{7}} = \sqrt[7]{0.5523}$

$1 + r = 0.9187$

$r = 0.9187 - 1$

$r = -0.0813$

$P(t) = 1720(1 - 0.0813)^{t}$

$P(t) = 1720(0.9187)^{t}$

Once the population drops below 150, the situation will be irreversible. When will this happen?

This is t when P(t) = 150. So

$P(t) = 1720(0.9187)^{t}$

$150 = 1720(0.9187)^{t}$

$(0.9187)^{t} = \frac{150}{1720}$

$(0.9187)^{t} = 0.0872$

It is important to know that:

$\log{a^{t}} = t\log{a}$

So we apply log to both sides

$\log{(0.9187)^{t}} = \log{0.0872}$

$t\log{0.9187} = \log{0.0872}$

$t = \frac{\log{0.0872}}{\log{0.9187}}$

$t = \frac{-1.0595}{-0.0368}$

$t = 28.79$

This will happen in 28.79 years.

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4 years ago

Which type of light provides general lighting for the scene and is often mounted so that it may be raised, lowered, or turned to

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Answer:

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