Answer:
False
Step-by-step
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Hoped I helped. Comment if I am right or not just let me know in the comments.
2(x+p)^2+q=2x^2+4px+(2p^2+q), compare with ..... 2x^2 + 8x+3 p=2,W=3-2p^2=-5, so the result is 2(x+2)^2-5
Slope formula: y2-y1/x2-x1
Part one:
-7-4/-7-(-7)
-11/0
Since the denominator is 0, the slope is undefined.
Part two:
-9-(-9)/2-(-5)
0/7
Since the numerator is 0, the slope is 0.
Best of Luck!
Answer:
Step-by-step explanation:
It is assumed PQS and RQS are similar triangles.
<u>The ratio of corresponding sides is equal:</u>
<u>Substitute side lengths and solve for x:</u>
- 15/(3x - 4) = 21/(5x - 16)
- 15(5x - 16) = 21(3x - 4)
- 5(5x - 16) = 7(3x - 4)
- 25x - 80 = 21x - 28
- 25x - 21x = 80 - 28
- 4x = 52
- x = 52/4
- x = 13
Answer:
It's is a negative one ( -1 )
Step-by-step explanation:
The explanation is in the question, if you draw the line you will see it.