Answer:
<em>AB = 5√2</em>
<em>AC = √145</em>
<em>BC = √65</em>
Step-by-step explanation:
Using the formula for calculating the distance between two points
D = √(x2-x1)²+(y2-y1)²
For AB A(-3,6),B(2,1),
AB = √(2+3)²+(1-6)²
AB = √(5)²+(-5)²
AB = √25+25
AB = √50
<em>AB = 5√2</em>
For AC A(-3,6) and C(9,5)
AC = √(9+3)²+(5-6)²
AC = √(12)²+(-1)²
AC = √144+1
<em>AC = √145</em>
For BC B(2,1), and C(9,5)
BC = √(9-2)²+(5-1)²
BC = √(7)²+(4)²
BC = √49+16
<em>BC = √65</em>
<em></em>
<em>Since All the sides are difference, hence triangle ABC is a scalene triangle</em>
Answer:
x ≈ 54.8°
Step-by-step explanation:
Using the tangent ratio in the right triangle
tan x =
=
=
, then
x =
(
) ≈ 54.8° ( to the nearest tenth )
Answer:
-3 < x ≤ 6
Step-by-step explanation:
Left side is exclusive, right side is inclusive, hence the < and ≤, respectively.
original slope = -4/3
parallel slope = -4/3
Explanation:
For a line to be parallel to anpother line, the slope of both lines must be equal.
We need to find the slope of the given line by picking any two points on the line.
Using points (-6, 5) and (0, -3)
slope formula:


The equation of the given line: y = mx + b
b = y-intercept = -3
y = -4/3x - 3
The equation line parallel to the one above could be:
y = -4/3 x + 7
This because the slope are the same
original slope = -4/3
parallel slope = -4/3
plotting the graph of the lline parallel to the first one: