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mr Goodwill [35]
3 years ago
12

(x - 4/6) = (x + 2/12) what is x please show your work.

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0
-4/6 times 2 is -8/12

x - 8/12= x + 2/12

0=10/12
0=5/6

but since 0 does not equal 5/6, this will be no solution
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What is 3/5 divided by 2 1/2 by the lowest quotient
Brilliant_brown [7]

Answer:

<h2>\frac{6}{25}</h2>

Step-by-step explanation:

<h3>\frac{3}{5} ÷ \frac{5}{2} = \frac{3}{5} ÷ \frac{2}{5} = \frac{6}{25}</h3>
7 0
3 years ago
Write an equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the l
mamaluj [8]

The equation in slope-intercept form for the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5 is y = \frac{3}{4}x - \frac{5}{4}

<em><u>Solution:</u></em>

<em><u>The slope intercept form is given as:</u></em>

y = mx + c ----- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given that the line that passes through the point  ( -1 , -2 )  and is perpendicular to the line − 4 x − 3 y  =  − 5

Given line is perpendicular to  − 4 x − 3 y  =  − 5

− 4 x − 3 y  =  − 5

-3y = 4x - 5

3y = -4x + 5

y = \frac{-4x}{3} + \frac{5}{3}

On comparing the above equation with eqn 1, we get,

m = \frac{-4}{3}

We know that product of slope of a line and slope of line perpendicular to it is -1

\frac{-4}{3} \times \text{ slope of line perpendicular to it}= -1\\\\\text{ slope of line perpendicular to it} = \frac{3}{4}

Given point is (-1, -2)

Now we have to find the equation of line passing through (-1, -2) with slope m = \frac{3}{4}

Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1

-2 = \frac{3}{4}(-1) + c\\\\-2 = \frac{-3}{4} + c\\\\c = - 2 + \frac{3}{4}\\\\c = \frac{-5}{4}

\text{ substitute } c = \frac{-5}{4} \text{ and } m = \frac{3}{4} \text{ in eqn 1}

y = \frac{3}{4} \times x + \frac{-5}{4}\\\\y = \frac{3}{4}x - \frac{5}{4}

Thus the required equation of line is found

8 0
2 years ago
Solve sec2theta + tantheta - 3 =0 for 0
Serhud [2]

Answer:

Ф = \frac{\pi }{4} ,\frac{5\pi}{4}

Step-by-step explanation:

It is a bit difficult to input the work here, so I uploaded an image

  • First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
  • Then we can combine like terms
  • Then we can factor this as a polynomial function
  • Then we can set each term equal to zero and solve for Ф
  • The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
  • The second term tan(Ф) - 1 = 0 has two solutions of \frac{\pi}{4} and \frac{5\pi}{4} so these are the solutions to the problem

7 0
3 years ago
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