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Thepotemich [5.8K]
3 years ago
9

A chocolate chip cookies recipe calls for 4 and 1/4 cups of chocolate chips to make 10 dozen cookies Based on this recipe, how m

any cups of chocolate are needed to make 25 dozen cookies?
Mathematics
2 answers:
ELEN [110]3 years ago
8 0

Answer:

10 and5/8 cups

Step-by-step explanation:

4 and 4/1 cups for 10x12 cookies

17/4 cups for 120 cookies

34/8 cups for 120 cookies

17/8 cups for 60 cookies

we need to find 25 x 12 cookies = 300 = 120+120+60

17/8 + 34/8 +34/8 =85/8 =10and 5/8 cups

ale4655 [162]3 years ago
7 0

Answer:

The answer is 10 5/8

Step-by-step explanation:

You might be interested in
Geela makes orange paint with 5 parts yellow to
Oxana [17]
Answer:

Geela would need 9 yellow parts


Explanation:

Originally, the Geela needed more yellow than red and the difference was 4 parts.

6-2=4 parts


4 parts + 5 parts of yellow = 9 yellow parts.
3 0
3 years ago
90 POINTS| PLEASE ANSWER ASAP|
shtirl [24]

For A:

You add the probabilities to get the answer to A: = .75, or 3/4

Note that the probability of ALL THREE of them hitting would be 1/3 x 1/4 x 1/5.

For B:

2/3 and 3/4 is the probability of the other two people MISSING (the remainder of 1/3, 1/4)

1.0 = 100% chance to hit the target, so 1.0 x 2/3 x 3/4 = 1/2

Mark's chance of hitting is 1/5, so do 1/2 x 1/5, = 1/10

5 0
3 years ago
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
CINDY made costume decorations. She used 1/10 of a meter of ribbon for each decoration which she got by cutting 3/10 of a meter
Brilliant_brown [7]

Answer:

Cindy made 3 decorations with the ribbons

Step-by-step explanation:

Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.

If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10

i.e 3/10 ÷ 1/10

= 3/10 × 10/1

= 3 decorations.

That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).

3 0
3 years ago
Read 2 more answers
Help me with this question
kaheart [24]
First combine like terms and put the expression in standard form. This expression is now in simplest form and cannot be simplified anymore.
3a + 10ab - 7a^2b - 10ab^2 + 12ab - (-4) + (-a^2b) - 5a
-10ab^2 - 8a^2b -2a + 24ab - (-4)

Hope this helps

5 0
3 years ago
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