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Thepotemich [5.8K]
3 years ago
9

A chocolate chip cookies recipe calls for 4 and 1/4 cups of chocolate chips to make 10 dozen cookies Based on this recipe, how m

any cups of chocolate are needed to make 25 dozen cookies?
Mathematics
2 answers:
ELEN [110]3 years ago
8 0

Answer:

10 and5/8 cups

Step-by-step explanation:

4 and 4/1 cups for 10x12 cookies

17/4 cups for 120 cookies

34/8 cups for 120 cookies

17/8 cups for 60 cookies

we need to find 25 x 12 cookies = 300 = 120+120+60

17/8 + 34/8 +34/8 =85/8 =10and 5/8 cups

ale4655 [162]3 years ago
7 0

Answer:

The answer is 10 5/8

Step-by-step explanation:

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1 Point<br> The circle below is centered at (-3, 2) and has a radius of 3. What is its<br> equation?
arlik [135]

Answer:

(x + 3)^2 + (y - 2)^2 = 9

Step-by-step explanation:

<u>Equation for a circle:  (x – h)^2 + (y – k)^2 = r^2</u>

<u />

<u>Step 1:  Determine what h, k, and r are</u>

<em>h is the x value of the point:  -3</em>

<em>k is the y value of the point:  2</em>

<em>r is the radius of the circle:  3</em>

<u>Step 2:  Plug in and solve</u>

(x – h)^2 + (y – k)^2 = r^2

(x – (-3))^2 + (y – (2))^2 = (3)^2

<em>(x + 3)^2 + (y - 2)^2 = 9</em>

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Answer:  (x + 3)^2 + (y - 2)^2 = 9

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4 years ago
What are the zeros of f(x)=(x+5)(x-9)?
klemol [59]

Answer:

x= -5

x= 9

Step-by-step explanation:

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3 years ago
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Tell which number is greater.<br><br> 76%, 0.67
Mariana [72]

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76%

Step-by-step explanation:

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8 0
3 years ago
What is the root of 320 simplified?
Crazy boy [7]

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Step-by-step explanation:

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3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

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The rate of increase after 1 day is 0.09

8 0
3 years ago
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