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4 years ago

11

What causes the phases of our moon

1 answer:

Helga [31]4 years ago

4 0

sunlight, and the position of the earth

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A student redid the experiment of mixing room temperature water and warm

Len [333]

Answer:

I think B or C it won't lower so I'll go with B bc warm water is hotter than regular temp water

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3 years ago

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Based on the thermodynamic functions of enthalpy and entropy, can an unfavorable reaction that has a positive δg at rt be made f

Over [174]

I believe that the answer to the question provided above is yes, an unfavorable reaction that has a positive δg at rt be made favorable by increasing the reaction temperature.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

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4 years ago

A car has an initial velocity of 9 km/hr and a final velocity of 66 km/hr. What is the cars average velocity? Use one of the fol

Karolina [17]

Answer:

velocity of 66 km/hr.

Explanation:

7 0

3 years ago

The density of air under normal conditions is about 1.2 kg/m3. For a wind speed of 10 m/s, find

den301095 [7]

Answer:

The density’ is 5.46

Explanation:

3 0

3 years ago

Based on the simple blackbody radiation model described in class, answer the following question. The planets Mars and Venus have

Lera25 [3.4K]

Answer:

The extent of greenhouse effect on mars is $G_m = 87 K$

Explanation:

From the question we are told that

The albedo value of Mars is $A_1 = 0.15$

The albedo value of Mars is $A_2 = 0.15$

The surface temperature of Mars is $T_1 = 220 K$

The surface temperature of Venus is $T_2 = 700 K$

The distance of Mars from the sun is $d_m = 2.28*10^8 \ km = 2.28*10^8* 1000 = 2.28*10^{11} \ m$

The distance of Venus from sun is $d_v = 1.08 *10^{8} \ km = 1.08 *10^{8} * 1000 = 1.08 *10^{11} \ m$

The radius of the sun is $R = 7*10^{8} \ m$

The energy flux is $E = 6.28 * 10^{7} W/m^2$

The solar constant for Mars is mathematically represented as

$T = [\frac{E R^2 (1- A_1)}{\sigma d_m} ]$

Where $\sigma$ is the Stefan's constant with a value $\sigma = 5.6*10^{-8} \ Wm^{-2} K^{-4}$

So substituting values

$T = \frac{6.28 *10^{7} * (7*10^8)^2 * (1-0.15)}{(5.67 *10^{-8}) * (2.28 *10^{11})^2)}$

$T = 307K$

So the greenhouse effect on Mars is

$G_m = T - T_1$

$G_m = 307 - 220$

$G_m = 87 K$

3 0

4 years ago