well i see 25 % but half of the visable surface is illuminated
Answer:
Option D
490 J
Explanation:
When at a height of 100 am above and released, the ball initially posses only potential energy. When it falls, some potential energy is converted to kinetic energy.
Initial potential energy= mgh where m is the mass, g is the acceleration due to gravity and h is height. Substituting 1 Kg for m, 9.81 for g and 100 m for h then
PE initial = 1*9.81*100= 981 J
At 50 m, PE will be 1*9.81*50=490.5 J
Subtracting PE at 50 m from initial PE we get the energy that has been converted to kinetic energy hence
981-490.5= 490.5 J
Approximately, 490 J
We are given with 98 Newton weight of an object on the surface of the earth with an acceleration equal to 9.8 m/s2. This means the mass of the object is equal to 98/9.8 or 10 kg. Hence the weight of the object 10,000 kilometers above sea level where acceleration is 1.49 m/s2 is 14.9 Newtons.
<span>It is important to determine their location before operating on an unfamiliar body of water because they are often difficult to spot, even with local charts. If you don't know what you're doing you can get stuck and that can be a huge problem, so it's necessary to know what you're doing and where they are located.</span>
Answer:
Explanation:
Voltage, V = 12 V
Charge, q = 2 micro coulomb = 2 x 10^-6 C
Work = energy
W = 0.5 x q x V
W = 0.5 x 2 x 10^-6 x 12
W = 12 x 10^-6 J
