Meg dilated triangle W by a factor less than 1. Then she performed other transformations that were not dilations to create simil
ar triangle W′.
Which could be the vertices of triangle W?
A. X(–2, 2), Y(–10, 2), Z(–6, 10)
B. X(2, 2), Y(4, 2), Z(3, 4)
C. X(0, 2), Y(4, 2), Z(2, –6)
D. X(2, 2), Y(2, 6), Z(4, 6)
Which could be the vertices of triangle W?
A. X(–2, 2), Y(–10, 2), Z(–6, 10)
B. X(2, 2), Y(4, 2), Z(3, 4)
C. X(0, 2), Y(4, 2), Z(2, –6)
D. X(2, 2), Y(2, 6), Z(4, 6)
2 answers:
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The perimeter of a shape is the sum of its side lengths
The expressions for the perimeter of the frame are 4(l + 2) and 4l + 8
<h3>How to determine the perimeter of the shape</h3>The side length of the frame is given as l
So, the perimeter of the frame is
:
When 2 inches are added to each length, the perimeter of the frame becomes
Expand
Hence, the expressions for the perimeter of the frame are 4(l + 2) and 4l + 8
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Answer:
<em>The coordinates of the vertex are (-1,-4).</em>
Step-by-step explanation:
<u>Equation of the Quadratic Function </u>
The vertex form of the quadratic function has the following equation:
Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.
We are given the function:
We must transform the equation above by completing squares:
The first two terms can be completed to be the square of a binomial. Recall the identity:
Thus if we add and subtract 1:
Operating:
The trinomial in parentheses is a perfect square:
Adding 4:
Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).
The coordinates of the vertex are (-1,-4).