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Vlad [161]
4 years ago
8

Is this a right triangle?Use the Pythagorean Theorem to find out! [picture above]​

Mathematics
1 answer:
S_A_V [24]4 years ago
8 0
No, 10^2 + 14^2 ≠ 18^2
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Solve the Fahrenheit equation for Celsius
horrorfan [7]
The first step you should do is subtract 32 from both sides so your answer will turn out like this -

F = (9/5) C + 32
- 
F - 32 = (9/5)

Then we will multiply both sides by 5. 

5 ( F - 32 ) = 9 C

Divide both sides by 9 to isolate C.

(5/9)  ( F - 32 ) = C

So the answer is :

C = (5/9) ( F - 32 )

Hope this helps :)

7 0
3 years ago
Read 2 more answers
One morning during the spring break, Jose ran 13 miles up hill in the rain. That afternoon Jose ran up the hill 3 2/3 faster whe
netineya [11]

Answer:

The answer to your question is 13 miles

Step-by-step explanation:

In the question is not mentioned the distance that Jose one during the afternoon, it is only mentioned that he ran faster than in the morning so we can imply that the distance was the same in both occasions, just he ran faster in the afternoon because there was no rain.

6 0
3 years ago
Find the sum of 5+(-7)=?. Use a number line to verify your answer
Nina [5.8K]

Answer:

-2

Step-by-step explanation:

5+(-7) is the same as saying 5-7, so lets looks at this

6 0
4 years ago
Read 2 more answers
20) A jar filled with only dimes and quarters contains a total of 23 coins. The value of all the coins in
nignag [31]

Answer:

6 quarters

Step-by-step explanation:

6 quarters = 1.50

So that would leave 17 dimes left

And 17 dimes left equal 1.70

1.50 + 1.70 = 3.20

8 0
3 years ago
Which of the following shows the division problem??
elena-14-01-66 [18.8K]

we are given

\frac{3x^2-4x+9}{x-2}

we can see that

numerator is

3x^2-4x+9

and denominator is

x-2

We always put coefficient of numerator inside box

we can see that coefficient of numerators are 3 , -4 and 9

and in the left side , we put value of x after putting denominator =0

x-2=0

x=2

so, left side will be 2

so, option-D..................Answer

7 0
3 years ago
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