Answer:
We have to prove
sin(α+β)-sin(α-β)=2 cos α sin β
We will take the left hand side to prove it equal to right hand side
So,
=sin(α+β)-sin(α-β) Eqn 1
We will use the following identities:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Putting the identities in eqn 1
=sin(α+β)-sin(α-β)
=[ sin α cos β+cos α sin β ]-[sin α cos β-cos α sin β ]
=sin α cos β+cos α sin β- sinα cos β+cos α sin β
sinα cosβ will be cancelled.
=cos α sin β+ cos α sin β
=2 cos α sin β
Hence,
sin(α+β)-sin(α-β)=2 cos α sin β
Looks to be adjacent and virtually all of them are there
Answer:
Hi! Saw your comment saying you got it, congrats! I hope you are having an amazing day/night and I wish you luck with the rest of your studies! I hope you don't mind that I use this for some points! <3
Answer:
-4
Step-by-step explanation:
You multiply -13*-4=52
It is B.
The underlined ≥ symbols a closed circle, and any number bigger than 3 if you multiply it with 4 and solve the equation, your answer would be reasonable
