Answer: 2b +2f =5----------(1)
3b +4f =8.5---------(2)
From eqn 1
2f = 5 -2b
f = (2.5 - b)
Put f =(2.5-b) in eqn 1
3b + 4(2.5-b) =8.5
3b +9 - 4b =8.5
-b = -0.5
b = $0.5
Step-by-step explanation:
<em>Greetings from Brasil... </em>
For the composite function FоG(X) = F(G(X)), just replace the function G(X) in the X of F(X):
F(X) = X + 4
G(X) = 3X² - 7
F(X) = X + 4
F(G(X)) = [G(X)] + 4
F(G(X)) = [3X² - 7] + 4
F(G(X)) = 3X² - 7 + 4
<h2>F(G(X)) = 3X² - 3</h2>
Answer:
9. Triangle ABQ is congruent to Triangle BAP because of SAS congruency
10. x=5, y isn't shown anywhere
Step-by-step explanation:
9. The side AB is shared between the two triangles.
It is given that angle A and angle B are congruent.
It is given that AQ is congruent with BP.
Using these three, you can say that Triangle ABQ is congruent to Triangle BAP because of SAS congruency.
10. 7x-4=31 (given)
x=5
Do the same thing with y.
Answer:
The answer is that adult tickets cost $44.50 and child tickets cost $19.
Step-by-step explanation:
Let c = the cost of child tickets and a = the cost of adult tickets.
The total amount is equal to the number of adult tickets time the cost of adult tickets plus the number of child tickets times the cost of child tickets. Set up two equations:
2a + 4c = 165
4a + 3c = 235
Solve the top equation for a:
2a + 4c = 165
2a = 165 - 4c
a = 165/2 - 4c/2
a = 82.5 - 2c
Substitute into the second equation:
4a + 3c = 235
4(82.5 - 2c) + 3c = 235
330 - 8c + 3c = 235
-5c = -95
c = -95 / -5 = 19, so child ticket cost $19.
Solve for a:
a = 82.50 - 2c
a = 82.50 - 2(19)
a = 82.50 - 38
a = $44.50, so adult tickets cost $44.50.
Proof using the first equation for the Johnson family:
2a + 4c = 165
2(44.50) + 4(19) = 165
89 + 76 = 165
165 = 165
Proof using the second equation for the Robison family:
4a + 3c = 235
4(44.50) + 3(19) = 235
178 + 57 = 235
235 = 235
How someone supposed to know what the table looks like..... at least add the table