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MrMuchimi
3 years ago
8

A builder needs to tile a 7 foot by 8 foot room with one-foot square tiles. how many tiles will she need?

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0
I believe that she will need 56 square tiles. You get this by doing 7 times 8 which is 56. Then, since each tile is a one-foot square tile, you would need 56 tiles to cover the whole floor. 
Ksju [112]3 years ago
5 0

Answer:   56 tiles.

Step-by-step explanation:

Given : A builder needs to tile a 7 foot by 8 foot room with one-foot square tiles.

i.e. Area of a tile = 1 square foot.

Now, the area of the room is given by :-

\text{Area of room}=6\times8=56\text{ ft}^2

Now, the number of tiles required is given by :-

n=\dfrac{\text{Area of room}}{\text{Area of one tile}}\\\\=\dfrac{56}{1}=56

Hence, she will need 56 tiles.

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How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
Select the correct answer.
Molodets [167]

Answer:

A.

to discuss Shays's Rebellion in Massachusetts

3 0
2 years ago
Sally has Christmas lights the roof is 16 feet high the ladder is 20 ft long how far away is letter from wall
lesantik [10]
It should be 12 ft away from the wall. Not 4 ft. You do not just subtract the difference because as you pull it away from the wall, the ladder is mostly moving horizontally with only a small vertical change.

You can use Pythagorean Theorem to find the answer. Think of the ladder as the hypotenuse of a right triangle with the wall and the ground as the legs.

a^2 + b^2 = c^2

16^2 + b^2 = 20^2

b^2 = 20^2 - 16^2

b^2 = 144

b = 12 ft






4 0
3 years ago
a rectangular prism is 5 meters long, 17 meters wide, and 4 meters high. what is the surface area of the rectangular prism?
Mars2501 [29]

The surface area of rectangular prism is 346 square meters.

Given the figure is rectangular prism.

We know that the surface area of rectangular prism with length L, width W and height H is = 2(LW+WH+LH)

Given that the length of prism = 5 m

Width of prism = 17 m

Height of prism = 4 m

So the total surface area of the rectangular prism is given by,

= 2 [5*17 + 17*4 + 4*5]

= 2 [85 + 68 + 20]

= 2*173

= 346 square meters

Hence the surface area of rectangular prism is 346 square meters.

To know more about Rectangular Prism refer to:

brainly.com/question/24284033

#SPJ4

8 0
9 months ago
42?? I get confused with adding/ multiplying
Brut [27]
The answer is c pls mark me as brainless
4 0
3 years ago
Read 2 more answers
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