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3 years ago

Would you rather be bitten by 15% of 120 mosquitoes or 8% of 250 mosquitoes explain why

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

7 0

Answer:

15% of 120 mosquitoes

Step-by-step explanation:

15% of 120 is 18 while 8% of 250 is 20. 15% of 120 is less mosquitoes

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HELP ASAP PLEASE!!! 20 POINTS!

Elenna [48]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Use the expression "x + 2" to work this out

1 + (1 + 2) + (3 + 2) + (5 + 2) + (7 + 2) + (9 + 2) + (11 + 2 ) + (13 + 2) = 64

He will have saved $64

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0

3 years ago

Help me I have no idea how to do 18

sleet_krkn [62]

First, subtract px2 from both sides.

Now you have:

x3 - px2 = (1 - p) x1

Next, divide both sides by (1 - p)

So now you have

x3 - px2/(1 - p) = x1

...as your final answer

*You can decide if you want to leave the parenthesis in your final answer, I left them there so it could be visible where I put them. :)

5 0

3 years ago

On a certain day the exchange rate was 60 u.s dollars 50 euro. How many US dollars were 70 euro worth that day? Show that your a

gayaneshka [121]

This is what I got:

60/50 = X/70
70x60/59 = X
X = 84

8 0

3 years ago

Pls help me desperate for this answer !! <br><br><br> TB ≅ TC<br><br><br> TA ≅ AT

oee [108]

Answer:

its tb=tc g

Step-by-step explanation:

7 0

2 years ago

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$

$P = \frac{1701.56}{1.6}$

$P = 1063.48 W = 1.06 kW$

5 0

3 years ago