Question

An object, initially at rest, moves with a constant acceleration of 10 m/s2. How far will it travel in (a) 2.0 s and (b) 4.0 s? If this object had an initial velocity of 4 m/s, how far will it travel in (C) 2.0 s and (d) 4.0 s?

Answer 1

Explanation:

Initially, the object is at rest, u = 0

Acceleration of the object, $a=10\ m/s^2$

(a) Distance travel in 2 second can be calculated using second equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

$s=\dfrac{1}{2}\times 10\times 2^2=20\ m$

(b) Distance travel in 4 second can be calculated using second equation of motion as :

$s=\dfrac{1}{2}\times 10\times 4^2=80\ m$

(c) Initial velocity of the object, u = 4 m/s

$s=ut+\dfrac{1}{2}at^2$

$s=4\times 2+\dfrac{1}{2}\times 10\times 2^2=28\ m$

(d) $s=ut+\dfrac{1}{2}at^2$

$s=4\times 4+\dfrac{1}{2}\times 10\times 2^2=36\ m$

Hence, this is the required solution.