Answer:
charge Qint = 7.17 10⁻⁴ C
Explanation:
For this problem we must use Gauss's law
F = ∫ E. dA = Qint / εₙ
let's form a Gaussian surface that is parallel to the surface, for example, a Cube. As the field is vertical and perpendicular to the surface, the field lines and the area vector are parallel whereby the scalar product is reduced to an ordinary product.
Φ = E A = Qint / ε₀
A = 1 km² (1000 m / 1km)² = 1 10⁶ m²
We can calculate the charge
Qint = E A ε₀
Qint = 81 1 10⁶ 8.85 10⁻¹²
Qint = 7.17 10⁻⁴ C
C- Stratus clouds are the rainy clouds.
Hope this helps!
22 ft/s^2.
explanation: In this case, the velocity has increased by 60 mph in 4 seconds, so the average increase is 60/4 = 15 mph every second, or 15 mph/s.
Usually, you will want to use the same units of time throughout. In this case, you could multiply by the number of seconds in an hour to find out the change in velocity if it carried on travelling for that length of time. This would give the acceleration in units of mph/h, or mph^2.
If you want the answer in feet/s^2, then take your 15 mph/s answer, multiply by the number of feet in a mile (to get it to feet per hour per second) then divide by the number of seconds in an hour to get it to feet per second per second, or feet/s^2.
You should get 22 ft/s^2.
Answer:
250
Explanation:
I guess I don't know for sure
