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Gnoma [55]
3 years ago
8

An airplane used to drop water on brushfires is flying horizontally in a straight line at 180 mi/h at an altitude of 390 ft. Det

ermine the distance d at which the pilot should release the water so that it will hit the fire at B.
Physics
1 answer:
Arturiano [62]3 years ago
3 0

Answer:

The water should be released a distance of 1289.88 feet before the plane is on top of the bush fire.

Explanation:

Let's first find the time required for the water to fall down 390 ft onto the bush fire.

Initial Vertical Speed of water = 0

Distance to be covered = 390 ft

Acceleration due to gravity = 32.2 ft/s^2

s=u*t+\frac{1}{2} (a*t^2)

390=0*t+0.5(32.2*t^2)

t = 4.92 seconds

Thus the water should be dropped 4.92 seconds before the plane is over the bush fire. Now we can also find the distance d at which the pilot should release the water:

d = Speed of plane * time

Speed of plane = 180 / (60 * 60) = 0.05 mile/second

d = 0.05 * 4.92 = <u>0.246 miles</u>    OR    <u>1289.88 feet</u>

<u />

Thus, the water should be released a distance of 1289.88 feet before the plane is on top of the bush fire.

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Gnom [1K]

Answer:

8m * (μg/v)^2

Explanation:

k, the spring constant = ?

(k in terms of μ, m, g, and v.)

Frictional force = μmg

Note: lost KE is converted to work done against the friction + PE of the spring

1/2mv2 = μmgx + 1/2kx^2....equation i

Cancel the 1/2 on both sides

mv^2 = μmgx + kx^2

Lets recall that:

Due to frictional effect, further enegy will be lost when the spring recoils backward

Therefore

1/2kx^2 = μmgx..... equation ii

Let's substitute 1/2kx^2 in equation I for ii

So we can say that:

1/2mv^2 = (μmgx)+ μmgx

1/2mv^2 = 2 (μmgx)

1/4mv^2 = μmgx

Cancel out m on both sides

1/4v^2 = μgx

Make x subject of the formula

x = (1/4v^2) / (μg)...... equation iii

substitute x to equation ii

But first make k in equation ii subject of the formula

1/2kx^2 = μmgx

k = 2μmg/x

Now substitute x

k = 2μmg / ((1/4v^2) / (μg))

k = 2μmg * ((μg) / (1/4v^2))

k = 8m * (μg/v)^2

8m * (μg/v)^2

7 0
3 years ago
Un alumno menciona que al abrir la ventana de su casa sintió cómo el frío ingresaba a su cuerpo. Menciona cuál es la verdadera r
stepan [7]

Answer:

My believe the answer is

A.) or B.)

Explanation:

Here is why I think A is the answer.

If we use the process of elimination, it would look like this,

a) Porque el aire tiene una temperatura menor que la de su cuerpo; por eso se propaga más rápido.

<em>This makes sense because we all know in winter the weather is very cold and freezing.</em>

b) Porque la temperatura de su cuerpo, siente el aire frio que entra por la ventana.

<em>I feel like this answer is the question, but it could also be an answer, sorry, I'm a little uncertain.</em>

c) Porque el calor de su cuerpo se propaga al medio ambiente, al ser la temperatura del niño mayor que la del aire exterior.

<em>This answer has nothing to do with the question, plus it is very false, our body heat is not enough to overcome the very cold temperature from outside.</em>

d) Porque la temperatura del aire es igual a la temperatura del cuerpo.

<em>This is false because again our body heat is not even compared to the freezing cold temperatures from the winter.</em>

<em />

<em />

<h2>Well, have a nice rest of the day!</h2><h3>ba baiii!</h3>
3 0
3 years ago
what is the acceleration of a softball if it has a mass of 0.50kg and hits the catcher’s glove with a force of 25 N
Kitty [74]

Answer:

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force=25N

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Now,

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25÷0.50=a

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hope this may help you!!!!

3 0
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Answer:

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Explanation:

The unit of their efforts can be derived from the formula of power which is given by the product of mass, acceleration and distance (the product is energy with unit joules) divided by time taken to complete the task (unit is seconds)

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Apply SUVAT

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