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3 years ago

Which property of sound waves decreases as the square of the distance from the source increases?

Physics

1 answer:

Vitek1552 [10]3 years ago

3 0

Answer:

Intensity

Explanation:

The intensity of a sound wave is equal to the ratio between to the power emitted by the source divided by the area of the spherical surface through which the wave propagates:

$I=\frac{P}{4\pi r^2}$

where

P is the power

$4\pi r^2$ is the area of the spherical surface

r is the distance from the source

As we see from the formula, the intensity is inversely proportional to the square of the distance from the source:

$I\propto \frac{1}{r^2}$

so, intensity is the correct answer.

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Examples of structure or machine parts that may fail due to bending

Alex_Xolod [135]

Answer:

Structural failure is initiated when a material is stressed beyond its strength limit, causing fracture or excessive deformations; one limit state that must be accounted for in structural design is ultimate failure strength.Compressive, tensile, bending and buckling are the basic types of structural failure for construction elements. These are caused due to faults in design and construction

7 0

3 years ago

A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o

Andrej [43]

Answer:

Recoil speed, $1.17\times 10^{-5}\ m/s$

Explanation:

Given that,

Mass of the comet fragment, $m_1=1.96\times 10^{13}\ kg$

Speed of the comet fragment, $v_1=6.5\times 10^4\ m/s$

Mass of Callisto, $m_2=1.08\times 10^{23}\ kg$

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

$m_1v_1=(m_2+m_2)V$

V is recoil speed of Callisto immediately after the collision.

$V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s$

So, the recoil speed of Callisto immediately after the collision is $1.17\times 10^{-5}\ m/s$

6 0

3 years ago

An astronaut's pack weighs 17.5 N when she is on earth, but only 3.24 N when she is on the surface of an asteroid. What is the a

Nimfa-mama [501]

Answer:

a= 1.81 m/s²

Explanation:

Ratio of the weights on both surfaces can be calculated as,

$\frac{W_{a} }{W_{E} }$ = $\frac{ma}{mg}$

Here;

Wa is the weight on the asteroid, $W_{E}$ is weight on earth,

m is mass of pack, a is acceleration due to an asteroid and

g is acceleration due to gravity.

Rearrange above equation for a,

a=g ( $\frac{Wa}{W_{E} }$ )

Substitute 3.24 N for Wa, 17.5 N for $W_{E}$ ,

9.81 m/s² for g in the above equation,

a= 9.81( $\frac{3.24}{17.5}$ )

a= 1.81 m/s²

7 0

4 years ago

A ball is thrown directly downward with an initial speed of 8.75 m/s, from a height of 21.0 m. after what interval does the ball

gayaneshka [121]

There you go!
as it is unnecessary to find velocity, so use the equation with v
remember to take all directions downwards as it is more convenient to calculate
after substituting the values, you have to reject the negative answed as time must be+
:)

8 0

4 years ago

What is the main source that drives global climate

aivan3 [116]

Pollution is a giant sorce to global warming

8 0

3 years ago