Equation: <span>3b+4b^2-a^3
Given: </span><span>a=3 & b=-5
Plug 3 in for (a) and -5 in for (b):
</span><span>3(-5)+4(-5)^2-(3)^3
</span>
Now follow PEMDAS:
<span>3(-5) + 4(-5)^2 - (3)^3
</span>-15 + 4(-5)^2 - (3)^3
-15 + 100 - (3)^3
-15 + 100 - 27
85 - 27
58
the asnwer is 58.
Answer:
X>_1 and x<_7
Step-by-step explanation:
Answer:
The responses to these question can be defined as follows:
Step-by-step explanation:
For point a:

For point b:


Answer:
24-6x
Step-by-step explanation:
To distribute, you multiply the number outside the parenthesis by each number inside, keeping in mind the signs.
So, 6(4-x) = 6(4) - 6(x) = 24-6x
Aₙ = 7n+4
n = 12 thus
a₁₂ = 7(12) + 4