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ella [17]
3 years ago
14

F(x)=4x4−5x3−2x+6 and g(x)=3x3−4x2−2x+1 . What is f(x)+g(x) ?

Mathematics
1 answer:
igomit [66]3 years ago
6 0
4*4-5*3-2x+6=  -x-7/2  slope = 2

3 * 3 - 4 *2 -2x +1=  - x - 2/2 slope = -2

2 + -2 = 0
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In the collection of beads, StartFraction 4 Over 20 EndFraction are blue. Which model shows the percent of beads that are blue?
jolli1 [7]

Option B model shows the percent of beads that are blue.

Solution:

Fraction of beads blue = \frac{4}{20}

To convert it into percent multiply the fraction by 100.

$\text {Percent of} \ \frac{4}{20}=\frac{4}{20}\times 100\%

                     $=\frac{4\times 100}{20} \%

Cancel the common factors, we get

                    = 20%

                    $=\frac{20}{100}

This means total number of boxes 100 and shaded in blue color 20.

Therefore option 2 represents \frac{20}{100}.

Hence option B model shows the percent of beads that are blue.

8 0
3 years ago
8+4(s-4t) simplify the expression. HELP, 20 POINTS
ella [17]
8+ 4s -16t= 4 (2+s-4t)
5 0
3 years ago
Jerry started doing sit ups every day. The first day he did 18 sit ups. Every day after that he did 4 more sit ups than he had d
Alexandra [31]

Answer:

10

Step-by-step explanation:

6 0
2 years ago
(Square root of 12-4) (4+Square root of 12) Rational or irrational
alukav5142 [94]
4 + square root of 12 is 7.464101615 and it's irrational
8 0
3 years ago
5,049 +48=105
Alborosie
<h2>Solution (a) :-</h2>

Let the cost of the less expensive comic book be x .

Then :-

1284 - 11x = x

Using this equation , we can find the cost of the less expensive comic book .

Price of the less expensive book :-

1284 - 11x = x

11x + x = 1284

12x = 1284

x =  \frac{1284}{12}

x = 107

Cost of the less expensive book is 107 .

Therefore , the epice of the less expensive book = $ 107 .

<h2>Solution (b) :-</h2>

Cost of the more expensive book = 11x

Which means :-

1284 - x = 11x

11x + x = 1284

12x = 1284

x = 107

11x = 11 \times 107

= 1177

Therefore , the price of the more expensive book = $ 1177 .

4 0
3 years ago
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