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ella [17]
3 years ago
14

F(x)=4x4−5x3−2x+6 and g(x)=3x3−4x2−2x+1 . What is f(x)+g(x) ?

Mathematics
1 answer:
igomit [66]3 years ago
6 0
4*4-5*3-2x+6=  -x-7/2  slope = 2

3 * 3 - 4 *2 -2x +1=  - x - 2/2 slope = -2

2 + -2 = 0
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Evaluate f(x) =3x+8 for x=1
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4 years ago
Simplify : 48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}]​
garri49 [273]

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86

Step-by-step explanation:

48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2{1 (2 - 15÷3)}] \\ 8[ - 2.5{ (2 - 15÷3)}] \\ 8[ - 2.5{ ( - 13÷3)}] \\ 8[ - 2.5{ (  - 4.3)}] \\ 8[10.75 { }] \\  = 86

8 0
2 years ago
Eden just bought a trough in the shape of a rectangular prism for her horses. She needs to know what volume of water to add to t
notsponge [240]

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let w represent the width, hence:

length = w + 33, height = w - 13

Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w

V(w) = w³ + 20w² - 429w

Rate of change = dV/dw = 3w² + 40w - 429

When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423

When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118

Rate = 10118 - 5423 = 4695 in³/in

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

Find out more on equation at: brainly.com/question/2972832

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4 0
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