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Ber [7]
2 years ago
15

Find the exact value of sinA in simplest radical form.

Mathematics
1 answer:
Ahat [919]2 years ago
3 0

Answer:

√7 / 4.

Step-by-step explanation:

Sin A = opposite side/ hypotenuse

= √63 / 12

= √9√7 / 12

=   3√7 / 12

=  √7 / 4.

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Find the point-slope equation for the line that passes through the points (-10,-20)and (1,-9)
qaws [65]
10-20=10so the answer and 10-9=1 so that's the answer

6 0
3 years ago
A Write an equivalent equation that does NOT contain decimals.
vampirchik [111]

                                                     <span>0.5x - 0.1 = -2.9

When you multiply each side of an equation by the same number,
you don't change the equation or its solution.  If you want to get rid
of the decimals, you could  multiply each side by  10.  Then the
equation is

                                                     5x - 1  =  -29

You should be able to solve that without help.
But I'm about to take your points, so here's
how to solve that equation:

                                            </span><span><span>5x - 1  =  -29

Add  1  to each side:        5x        =  -28

Divide each side by  5 :     x         =  -28 / 5

Simplify the solution:          x         =  -5 and 4/5 .

Again ... this is the same solution as the original equation
if we hadn't gotten rid of the decimals.

</span></span>
5 0
3 years ago
I need you to answer with a, b, c, d
solong [7]

To find the zeros of a quadratic fiunction given the equation you can use the next quadratic formula after equal the function to 0:

\begin{gathered} ax^2+bx+c=0 \\  \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}

For the given function:

f(x)=2x^2-10x-3x=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(2)(-3)}}{2(2)}x=\frac{10\pm\sqrt[]{100+24}}{4}\begin{gathered} x=\frac{10\pm\sqrt[]{124}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2\cdot2\cdot31}}{4} \\  \\ x=\frac{10\pm\sqrt[]{2^2\cdot31}}{4} \\  \\ x=\frac{10\pm2\sqrt[]{31}}{4} \\  \end{gathered}\begin{gathered} x_1=\frac{10}{4}+\frac{2\sqrt[]{31}}{4} \\  \\ x_1=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \end{gathered}\begin{gathered} x_2=\frac{10}{4}-\frac{2\sqrt[]{31}}{4} \\  \\ x_2=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Then, the zeros of the given quadratic function are:

\begin{gathered} x=\frac{5}{2}+\frac{\sqrt[]{31}}{2} \\  \\ x_{}=\frac{5}{2}-\frac{\sqrt[]{31}}{2} \end{gathered}

Answer: Third option

8 0
1 year ago
Bob's Skate Shop had a profit of $3,563 during the month of August. The company models its profit using p=x^2+10x-12 where x is
Elis [28]
I entered the equation into a graphing calculator. clicked table and then scrolled down to the profit of $3,563. 55 skateboards
you could also try this equation. B=the number attached to x so 10, a=the number attached to x^2(or in other equation x^3 etc) so 1 and c is the number, so -12.

3 0
3 years ago
The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi
dem82 [27]

Answer:

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require more than 15 minutes to grade

This is 1 subtracted by the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 16.3}{4.2}

Z = -0.31

Z = -0.31 has a pvalue of 0.3783.

1 - 0.3783 = 0.6217

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

8 0
3 years ago
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