Find the exact value of sinA in simplest radical form.
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Answer:
The roots of equations are as m = And n =
Step-by-step explanation:
The given quadratic equation is 2 x² + 6 x - 1 = 0
This equation is in form of a x² + b x + c = 0
Let the roots of the equation are ( m , n )
Now , sum of roots =
And products of roots =
So, m + n = = - 3
And m × n =
Or, (m - n)² = (m + n)² - 4mn
Or, (m - n)² = (-3)² - 4 ()
Or, (m - n)² = 9 + 2 = 11
I.e m - n =
Again m + n = - 3 And m - n =
Solving this two equation
(m + n) + ( m - n) = - 3 +
I.e 2 m = - 3 +
Or, m =
Similarly n =
Hence the roots of equations are as m = And n =
Answer