Answer:
80
Step-by-step explanation:
<u><em>A = Area of First Rectangle </em></u>
<u><em>B = Area of Second Rectangle </em></u>
<u><em>w = Width</em></u>
<u></u>
12(w)=320+B (1st Equation)
8(w) = B (2nd Equation)
w=B/8 <em><u>(Plug this value of w into the first equation)</u></em>
12B/8 = 320 +B <u><em>(you get this)</em></u>
12B= 2560 + 8B <u><em>(Simplify)</em></u>
4B = 2560
B =640 <em><u>plug this value into the 2nd equation</u></em>
8(w) = 640
w = 80
<em>To Test This</em>
12x80 = 960
8x80 = 640
<h3>960 - 640 = 320
<u><em>Therefore the answer is correct the width is 80</em></u></h3>
<h3 />
Answer: The required solution is
Step-by-step explanation: We are given to solve the following differential equation :
Let us consider that
be an auxiliary solution of equation (i).
Then, we have
Substituting these values in equation (i), we get
![m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.](https://tex.z-dn.net/?f=m%5E2e%5E%7Bmt%7D%2B10me%5E%7Bmt%7D%2B25e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%5E2%2B10y%2B25%29e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B10m%2B25%3D0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7De%5E%7Bmt%7D%5Cneq0%5D%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B2%5Ctimes%20m%5Ctimes5%2B5%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%2B5%29%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20m%3D-5%2C-5.)
So, the general solution of the given equation is
Differentiating with respect to t, we get
According to the given conditions, we have
and
Thus, the required solution is
B = 7
7 x 6 = 42
42 + 6 = 48.
Trinomials simply have 3 terms. The answer is C
5.268 • 10 to the power of 13
( the decimal point would have to move 14 times to the left)
