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3 years ago

14

Please help me with all of them

2 answers:

kaheart [24]3 years ago

3 0

Answer:

Question 6 is 1/6

Question 5 is 5/9

Question 7 is 1/15

Question 8 is 3/20

Question 4 is 1/30

irakobra [83]3 years ago

3 0

Question 6= 1/6 this is an easy explanation ask if you need me to explain why

You might be interested in

Help Definitions please?

aliina [53]

Answer:

A linear pair is a pair of angles that share a side and a base. In other words, they are the two angles created along one line when two lines intersect. Linear pairs are always supplementary.

3 0

2 years ago

Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.

igor_vitrenko [27]

Answer:

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

$m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7$

So, the solution of the equation is

$y = Ae^{m_{1} t} + Be^{m_{2} t}$

where m₁ = 3 and m₂ = -7.

So,

$y = Ae^{3t} + Be^{-7t}$

Also,

$y' = 3Ae^{3t} - 7e^{-7t}$

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

$y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1 (1)$

$y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}$

Substituting A into (1) above, we have

$\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1 \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}$

Substituting B into A, we have

$A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}$

Substituting A and B into y, we have

$y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

So the solution to the differential equation is

$y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}$

6 0

3 years ago

Which numbers is a solution to x>10

IceJOKER [234]

14 > 10

all the numbers that bigger than 10 can replace x

6 0

3 years ago

Find two mixed numbers so that the sum is seven wholes and two eights and the difference is two wholes and four eigths

Alex_Xolod [135]

Answer:

Step-by-step explanation:

x + y = 7 + 2/8 = 58/8

x - y = 2 + 4/8 = 20/8

Add the equations together

2x = 78/8

x = 39/8

y = x - 20/8 = 19/8

x = 39/8 = 4⅞

y = 19/8 = 2⅜

8 0

3 years ago

What is the answer to -8x-9>-21

dybincka [34]

<h3>:- Solution</h3>

-8x - 9 > -21

Move -9 to right side

-8x > -21 + 9

-8x > -12

x < -12/-8

x < 3/2

the answer to -8x - 9 > -21 is <u>x</u><u> </u><u><</u><u> </u><u>3</u><u>/</u><u>2</u>

3 0

2 years ago