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Alborosie
3 years ago
14

Please help me with all of them

Mathematics
2 answers:
kaheart [24]3 years ago
3 0

Answer:

Question 6 is 1/6

Question 5 is 5/9

Question 7 is 1/15

Question 8 is 3/20

Question 4 is 1/30

irakobra [83]3 years ago
3 0
Question 6= 1/6 this is an easy explanation ask if you need me to explain why
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Find the solution to the system of equations: x + 3y = 7 and 2x + 4y = 8 1. Isolate x in the first equation: 2. Substitute the v
klemol [59]
X + 3y = 7
x = -3y + 7

2x + 4y = 8
2(-3y + 7) + 4y = 8
-6y + 14 + 4y = 8
-2y = 8 - 14
-2y = - 6
y = -6/-2
y = 3

x + 3y = 7
x + 3(3) = 7
x + 9 = 7
x = 7 - 9
x = -2

solution is (-2,3)
6 0
3 years ago
Read 2 more answers
If a line has a slope of 4 and contains the point (-2,5), what is its equation in slope form?
melomori [17]

Answer:

y-y1=m(x-x1)

y-5=4(x + 5)

y-5=4x+20

5. 5

y = 4x + 25

6 0
2 years ago
Sabrina wants to have an average of at least 90 on her quizzes. If she took three quizzes andearned a 95, 86 and 82, what is the
Marrrta [24]

Answer:

97

Step-by-step explanation:

<u>97 </u>+ 95 + 86 + 82 = 360

360 / 4 = <em>90</em>

<em />

i hope this helps :))

3 0
3 years ago
I need help plzz its due TODAYYY
kobusy [5.1K]

Answer:

1st box: Asso. prop= m+(4+x)

2nd box: Comm. Prop= m+4=4+m

3rd box: iden. prop= m+0=m

4th box: Zero prop: m x 0=0

3 0
3 years ago
National data indicates that​ 35% of households own a desktop computer. In a random sample of 570​ households, 40% owned a deskt
Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a​ desktop.

Step-by-step explanation:

We are given that National data indicates that​ 35% of households own a desktop computer.

In a random sample of 570​ households, 40% owned a desktop computer.

<em><u>Let p = population proportion of households who own a desktop computer</u></em>

SO, Null Hypothesis, H_0 : p = 25%   {means that 35% of households own a desktop computer}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 570​ households who owned a desktop computer = 40%

            n = sample of households = 570

So, <u><em>test statistics</em></u>  =  \frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }

                               =  2.437

<em>Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0
3 years ago
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