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3 years ago

10

Which graph below is a tree graph?

2 answers:

Degger [83]3 years ago

8 0

I think that it is the last one

Hope this helps

BigorU [14]3 years ago

7 0

Answer: D

Step-by-step explanation:

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You go to a Christmas fair with a big Ferris wheel. The wheel has ten seats, and two people are placed on each seat. Every minut

monitta

60 people have ridden the wheel in 30 minutes

The time is given as:

$Time =30 \minutes$

The number of seats on the wheel is given as:

$Seats = 10\\$

The number of people on a seat is given as:

$People =2$

Every minute a seat exits the platform.

This means that, 2 people exit the platform every minute

So, the number (n) of people that exit the platform after 30 minutes would be:

$n =People \times Time$

This gives

$n = 2\times 30$

Multiply

$n = 60$

Hence, 60 people have ridden the wheel

Read more about proportions at:

brainly.com/question/25567167

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2 years ago

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Perform the operation 0.5x0.5+0.5/0.5=

oksano4ka [1.4K]

I believe .5x.5 is .25 and .5/.5 is 1 so add 1 and .25 to get 1.25. Hopefully? (:

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3 years ago

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Is it true or false?? i will mark brainlest the correct answer

mrs_skeptik [129]

Answer:

True

Step-by-step explanation:

In order to calculate this, we simply need to replace the variable c with the value of -8 and solve the inequality.

-9c >= 63

-9 * -8 >= 63

72 >= 63

Since both values are negative the product will be positive. This product is 72 which is in fact greater than 63, thus making the statement True

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3 years ago

Cammie goes to the gym to exercise 4 times per week. Altogether how many times does she go to the gym in 10 weeks?

Tamiku [17]

The answer is 40 because if you multiply 4 times per week× for 10 weeks=40 times for ten weeks.

3 0

3 years ago

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A basketball player makes a free throw 82.6% of the time. The player attempts 5 free throws. Use a histogram of the binomial dis

DiKsa [7]

Answer:

The most likely outcome is exactly 4 free throws

Step-by-step explanation:

Given

$n = 5$ --- attempts

$p = 82.6\%$ ---- probability of a successful free throw

$p = 0.826$

Required

A histogram to show the most likely outcome

From the question, we understand that the distribution is binomial.

This is represented as:

$P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}$

For x = 0 to 5, where x represents the number of free throws; we have:

$P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(X = 0) = ^5C_0 * 0.826^0 * (1 - 0.826)^{5-0}$

$P(X = 0) = ^5C_0 * 0.826^0 * (0.174)^{5}$

$P(X = 0) = 1 * 1 * 0.000159 \approx 0.0002$

$P(X = 1) = ^5C_1 * 0.826^1 * (1 - 0.826)^{5-1}$

$P(X = 1) = ^5C_1 * 0.826^1 * (0.174)^4$

$P(X = 1) = 5 * 0.826 * 0.000917 \approx 0.0038$

$P(X = 2) = ^5C_2 * 0.826^2 * (1 - 0.826)^{5-2}$

$P(X = 2) = ^5C_2 * 0.826^2 * (0.174)^{3}$

$P(X = 2) = 10 * 0.682 * 0.005268 \approx 0.0359$

$P(X = 3) = ^5C_3 * 0.826^3 * (1 - 0.826)^{5-3}$

$P(X = 3) = ^5C_3 * 0.826^3 * (0.174)^2$

$P(X = 3) = 10 * 0.5636 * 0.030276 \approx 0.1706$

$P(X = 4) = ^5C_4 * 0.826^4 * (1 - 0.826)^{5-4}$

$P(X = 4) = 5 * 0.826^4 * (0.174)^1$

$P(X = 4) = 5 * 0.4655 * 0.174 \approx 0.4050$

$P(X = 5) = ^5C_5 * 0.826^5 * (1 - 0.826)^{5-5}\\$

$P(X = 5) = ^5C_5 * 0.826^5 * (0.174)^0$

$P(X = 5) = 1 * 0.3845 * 1 \approx 0.3845$

From the above computations, we have:

$P(X = 0) \approx 0.0002$

$P(X = 1) \approx 0.0038$

$P(X = 2) \approx 0.0359$

$P(X = 3) \approx 0.1706$

$P(X = 4) \approx 0.4050$

$P(X = 5) \approx 0.3845$

See attachment for histogram

<em>From the histogram, we can see that the most likely outcome is at: x = 4</em>

<em>Because it has the longest vertical bar (0.4050 or 40.5%)</em>

3 0

2 years ago