Answer:
84 ounces of pure gold
Step-by-step explanation:
Jess has 60 ounces of an alloy that is 40% gold. How many ounces of pure gold must be added to this alloy to create a new alloy that is 75% gold?
Pure gold = 100% gold
Let the number of ounces of pure gold = x
Hence, we have the equation
40% × 60 ounces + 100%× x ounces = 75%(60 + x)ounces
= 0.4 × 60 + 1x = 0.75(60 + x)
= 24 + x = 45 + 0.75x
Collect like terms
x - 0.75x = 45 - 24
0.25x = 21
x = 21/0.25
x = 84 ounces
Therefore, we need 84 ounces of pure gold
The practical domain would be all integers 10 to 50.<span />
Answer:
A: f(t) = log(t-1)+2
Step-by-step explanation:
Hopefully this helps!
The top one is correct …..correct is correct
So we know that

= 180
So if we multiply 290 by

then we can find its radians in terms of pi (if pi is 180 and you divide 180 by 180 you get one so frankly we multiplying by one so we are not breaking any mathematical rules because if you multiply an number by itself then you get back that number right ?
∴
simplify by dividing the numerator of the first term and denominator
of the second term by 10 and then multiplying normally
∴ 290° in radians in terms of pi =