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Rina8888 [55]
2 years ago
9

Create a graph showing the equations y=1/4x and y=1/4x-5. Explain how the graphs are the same and how their different

Mathematics
1 answer:
Eduardwww [97]2 years ago
7 0

Answer:{y=1/4x-5 [-10, 10, -5, 5]}

Step-by-step explanation:

The

−

5

part says that the

y

-intercept of this line is

−

5

. The

y

-intercept is the point at which a line crosses the

y

axis. Therefore,

x

is always

0

for the

y

intercept.

The

1

4

x

is implying that the slope or the gradient (same thing) of this line is

1

4

. Therefore,

R

i

s

e

R

u

n

=

1

4

.

R

i

s

e

R

u

n

can be expanded to

y

2

−

y

1

x

2

−

x

1

.

Since we already know that the point

{

0

,

−

5

}

lies on this line, let's substitute

x

2

for

0

and

y

2

for

−

5

.

−

5

−

y

1

0

−

x

1

=

1

4

Now, if you choose a point for

x

1

, you can simply work out

y

1

. For example, let's say I chose

4

.

−

5

−

y

1

0

−

4

=

1

4

=

−

5

−

y

1

−

4

=

1

4

Now, what makes

1

4

when divided by

−

4

? The answer is

−

1

.

Therefore, we need

−

1

on the numerator. We already have

−

5

, and

y

1

is negative, so the number

−

4

fits. So the coordinates for the 2nd point is

{

4

,

−

4

}

−

5

−

−

4

−

4

=

1

4

=

−

1

−

4

=

1

4

Now, with the points we have,

{

0

,

−

5

}

and

{

4

,

−

4

}

, we can graph this by plotting the points and joining them.

You should get this graph{y=1/4x-5 [-10, 10, -5, 5]}

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Musya8 [376]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Ln how many ways 5 person sitted in a round table having 8 seats?
kvasek [131]

Answer: First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

Step-by-step explanation:

First consider the case that ‘just’ 5 persons are seated around a round table.

Clearly, ‘just’ 5 persons can be seated around a round table in (5 - 1)! = 4! = 24 ways.

Now, one vacant chair is to be inserted among them.

Say, for a particular sitting arrangement ‘ABCDE’; there are 5 scopes available for inserting the vacant chair - between A and B, between B and C, between C and D, between D and E & between E and A.

So, there are 5*24 = 120 ways available that 5 persons can sit around a round table with 6 chairs.

5 0
3 years ago
(PLS HURRY ASAP 100 POINTS)
Sophie [7]

Answer:

  • D) 0.3125

====================

Total number of outcomes is 16, count of all outcomes.

Number of outcomes with 3 or more tiles is 5:

  • HTTT, THTT, TTHT, TTTH, TTTT

The probability is:

  • P = favorable outcomes / total outcomes
  • P(at least 3 tails) = 5/16 = 0.3125

Correct choice is D.

6 0
1 year ago
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