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uysha [10]
3 years ago
5

Find the percent composition for SF6 S =? % F =? %

Chemistry
1 answer:
goldenfox [79]3 years ago
6 0

Answer:

S = 21.92 %

F = 78.08 %

Explanation:

To find the percent composition of each element in SF6, we must find the molar mass of SF6 first.

Molar mass of SF6 = 32 + 19(6)

= 32 + 114

= 146g/mol

mass of Sulphur (S) in SF6 = 32g

mass of Fluorine (F) in SF6 = 114g

Percent composition = mass of element/molar mass of compound × 100

- % composition of S = 32/146 × 100 = 21.92%.

- % composition of F = 114/146 × 100 = 78.08%.

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How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
If 1.2 kilograms of rust forms on a bridge in 5 days, what should be the rate of reaction in grams per hour?
Dimas [21]
We have 1.2 kg of rust whithin 5 days.
the rate of reaction in grams per hour:

1.2 kg/5 day * 1000 g/kg * 1 day/24 hours = 10.0 grams/hour

hope this help
8 0
4 years ago
a little kitten jumps from a tree and hits the ground 2.6 seconds later.with this information calculate the cat's velocity right
Harlamova29_29 [7]
The initial velocity is equal zero 
and the cat falls freely so the acceleration equal 9.81 m/s^2 
V = Vo + g * t 
V = 0 + (9.81 * 2.6) 
V = 25.5 m/s 
3 0
3 years ago
The bonds S-S, O-H and Ca-Cl are, respectively, a) nonpolar covalent, polar covalent, ionic polar covalent, b)nonpolar covalent,
Brums [2.3K]

Answer:

nonpolar covalent, polar covalent, ionic

Explanation:

From the question ,

S - S Bond -

Both the atom are same , hence , making a non polar bond , because of no difference between the electronegativity of the atom ,

Hence , the S-S Bond is non polar covalent bond .

O-H bond -

The Oxygen atom is more electronegative than the hydrogen atom , so the bond is polar in nature .

And as the bond is formed by sharing ,

Therefore ,

O-H bond is polar covalent bond .

Ca-Cl bond -

Calcium is a metal , whereas , Chlorine is a non - metal , the bond is ionic in nature ,

Hence , Ca-Cl bond is  ionic  in nature .

7 0
3 years ago
some students believe that teachers are full of hot air. If I inhale 3.5 liters of gas at a temperature of 19 degrees Celsius an
Afina-wow [57]

Answer:

3.97 L

Explanation:

Data obtained from the question include the following:

Initial volume (V1) = 3.5 L

Initial temperature (T1) = 19 °C

Final temperature (T2) = 58 °C

Final volume (V2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be done as shown below:

Temperature (K) = temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 19 °C

Initial temperature (T1) = 19 °C + 273 = 292 K

Final temperature (T2) = 58 °C

Final temperature (T2) = 58 °C + 273 = 331 K

Finally, we shall determine the new volume of the gas by using Charles' law equation as shown below:

Initial volume (V1) = 3.5 L

Initial temperature (T1) = 292 K

Final temperature (T2) = 331 K

Final volume (V2) =..?

V1 /T1 = V2 /T2

3.5 /292 = V2 /331

Cross multiply

292 x V2 = 3.5 x 331

Divide both side by 292

V2 = (3.5 x 331) / 292

V2 = 3.97 L

Therefore, the new volume of the gas is 3.97 L.

5 0
3 years ago
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