Answer:
Her acceleration was 0.8 m/s².
Explanation:
Given data:
Final speed v₂ = 5.4 m/s
Initial speed v₁= 3.0 m/s
Initial time t₁ = 2 s
Final time t₂ = 5 s
Acceleration = ?
Solution:
acceleration = (v₂- v₁) / (t₂ - t₁)
acceleration = 5.4 - 3 / 5-2
acceleration = 2.4 / 3 = 0.8 m/s²
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Its a sercret code figure it out and the answer is yours
Answer: The object's mass, height off the ground, and the strength of gravity :)
Answer:
12 mol O2
Explanation:
This is assuming you're using a combustion equation of
2 H2S + 3O2 -> 2H2O + 2SO2
Next time include the equation because that is where you will find your mol to mol ratio
8 mol H2S x (3 mol O2 / 2 mol H2S) = 12 mol O2
The new temperature (in °C) of the gas, given the data is –148.20 °C
<h3>Data obtained from the question </h3>
- Initial temperature (T₁) = 149.05 °C = 149.05 + 273 = 422.05 K
- Initial pressure (P₁) = 349.84 KPa
- Volume = constant
- New pressure (P₂) = 103.45 KPa
- New temperature (T₂) =?
<h3>How to determine the new temperature </h3>
The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
Since the volume is constant, we have:
P₁ / T₁ = P₂ / T₂
349.84 / 422.05 = 103.45 / T₂
Cross multiply
349.84 × T₂ = 103.45 × 422.05
Divide both side by 349.84
T₂ = (103.45 × 422.05) / 349.84
T₂ = 124.80 K
Subtract 273 from 124.80 K to express in degree celsius
T₂ = 124.80 – 273
T₂ = –148.20 °C
Learn more about gas laws:
brainly.com/question/6844441
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