1.) Gas given off
2.) precipitate formed
3.) large amount of heat given off
4.) Color change
Answer:
C) 2CO + O₂ → 2CO₂
Explanation:
The equation C is correct.
2CO + O₂ → 2CO₂
This equation have four oxygen atom and two carbon atoms on both side of equation. So it is correctly balanced.
All others are incorrect:
A) CO + O₂ → CO₂
this is incorrect because there are three oxygen atoms on left while two atoms on right.
B) CO + 2O₂ → 2CO₂
this is incorrect because there are five oxygen atoms on left while four atoms on right.
D) 2CO + 2O₂ → 2CO₂
this is incorrect because there are six oxygen atoms on left while four atoms on right.
Answer:
280 mL
Explanation:
Given data:
Mass of CuSO₄ = 55.75 g
Molarity of CuSO₄ = 1.25 M
Volume of CuSO₄ = ?
Solution:
First of all we will calculate the number of moles.
Number of moles:
Number of moles = mass / molar mass
Number of moles = 55.75 g/ 159.6 g/mol
Number of moles = 0.35 mol
Volume of CuSO₄:
Molarity = number of moles / volume in litter
1.25 M = 0.35 mol / volume in litter
Volume in litter = 0.35 mol / 1.25 M
Volume in litter = 0.28 L
Volume in milliliter:
0.28 L × 1000 mL/ 1 L = 280 mL
Answer:
Tienes que poner los elementos de las clasificaciones del agua y sus nombres.
Explanation:
no se explicar pero busca las clasificaciones del agua y las pones nada mas.
