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Amiraneli [1.4K]
3 years ago
10

Convert a speed of 141 mi/h to units of feet per minute show work.

Chemistry
1 answer:
ozzi3 years ago
3 0

Answer:

12408 feet per minute

Explanation:

Given: Speed is 141 mi/h

To find: speed in units of feet per minute

Solution:

Use the following units to convert the given speed into feet per minute.

1 mile = 5280 foot

1 h = 60 minutes

Therefore,

141 mi/h =\frac{141(5280)}{60} =12408 feet per minute.

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Consider a 0.10 M aqueous benzoic acid, CeHeCOOH. The K benzoic acid. 6.5 x 10 for A) Write a balanced equation that shows the r
7nadin3 [17]

Answer:

a) C6H5COOH + H2O ↔ H3O+  +  C6H5COO-

b) [ H3O+ ] = 2.517 E-3 M

c) pH = 2.599

Explanation:

a) balanced equation:

C6H5COOH + H2O ↔ H3O+  +  C6H5COO-

⇒ Ka = ( [ H3O+ ] * [ C6H5COO- ] ) / [ C6H5COOH ] = 6.5 E-5

mass balance:

0.10 m = [ C6H5COO- ] + [ C6H5COOH ].....(1)

charge balance:

[ H3O+ ] = [ C6H5COO- ] + [ OH- ] .......[ OH- ] : comes from water, it's not significant

⇒ [ H3O+ ] = [ C6H5COO- ] .........(2)

b) (2) in (1):

⇒ 0.10 M = [ H3O+ ] + [ C6H5COOH ]

⇒ [ C6H5COOH ] = 0.10 - [ H3O+ ]

⇒ Ka = [ H3O+ ]² / ( 0.1 - [ H3O+ ] ) = 6.5 E-5

⇒ [ H3O+ ]² + 6.5 E-5 [ H3O+ ] - 6.5 E-6 = 0

⇒ [ H3O+ ] = 2.517 E-3 M

c) pH = - log [ H3O+ ]

⇒ pH = - Log ( 2.517 E-3 )

⇒ pH = 2.599

7 0
3 years ago
2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder
damaskus [11]

Answer:

<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

P_2 =  \frac{1 \times 196}{26}  =  \frac{196}{26}   \\ = 7.538461...

We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

3 0
2 years ago
Which substance forms a major component of matter in a plasma state?
arlik [135]

Answer:

i see lot of peeps like anime and so do i zero two and naruto

Explanation:

4 0
3 years ago
A sample of H2 gas (2.0 L) at 3.5 atm was combined with 1.5 L of N2 gas at 2.6 atm pressure at a constant temperature of 25 °C i
Tamiku [17]
For this system, we use Dalton's law of partial pressures where the total pressure of a gas mixture is said to be equal to the sum of the partial pressures of the gases. The partial pressure of each gas would be calculated by the product of the mole fraction and the original pressure of the gas. We do as follows:

Total pressure = x1P1 + x2P2
Total pressure = (2.0 / 7.0 )(3.5) + (1.5/7.0)(2.6)
Total pressure = 1.56 atm
4 0
3 years ago
During normal, relaxed respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. this is called t
Marianna [84]

During normal respiration, about 500ml of air enters and leaves the lungs with each respiratory cycle. This is called the<u> tidal volume</u>.

When a person is relaxed, the normal amount of air such a person breathes in and out is called the tidal volume. It is usually measured in millimeters. For the average adult male, it is 500ml, and the tidal volume of average adult female 400ml.

In order to regulate oxygen intake and expulsion of carbon dioxide, the lungs act as buffers in order to absorb the maximum amount of oxygen possible for respiration and other metabolic functions in the body.

When the tidal volume is above or below the 500ml mark, it could signal the presence of underlying pathological conditions like bronchitis, emphysema and asthma.

To find out more about tidal volume, visit:

brainly.com/question/17439101

#SPJ4

6 0
1 year ago
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