Answer:
Step-by-step explanation:
In ΔMOT and ΔMPR,
OT║PR and MR is a transverse,
Therefore, ∠MTO ≅ ∠MRP [Corresponding angles]
Similarly, OT║PR and MP is a transverse,
Therefore, ∠MOT ≅ ∠MPR [Corresponding angles]
ΔMOT ~ ΔMPR → [By AA postulate of similarity]
[Reason → Corresponding sides of the similar triangles are proportional]
[By segment addition postulate]
1 +
= 1 + 

In ΔTSR,
∠1 ≅ ∠2 [Given]
Therefore, TR ≅ SR [Sides opposite to the equal angles in a triangle are equal]
Therefore, 
Or 
Hence proved.