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Basile [38]
3 years ago
10

True or False: 1)0^6=1^5 2)7^3=7 times 3 3)2^4=4^2

Mathematics
2 answers:
Usimov [2.4K]3 years ago
6 0

Answer:

1. 0^6=0  1^5=1    False

2. 7^3=7*7*7=343 7*3=21  False

3. 2^4=2*2*2*2=16 4^2=4*4=16 True

saw5 [17]3 years ago
5 0

Answer:

1) False

2) False

3) True

Step-by-step explanation:

1) 0^6 = 0 and 1^5 = 1, so they are not equal.

2) 7^3 = 7*7*7= 343 and 7*3 = 21, so they are not equal.

3) 2^4 = 2*2*2*2 = 16 and 4^2 = 4*4 = 16, so they are equal.

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slamgirl [31]

Answer:

by straight line property

a+156=180

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7 0
3 years ago
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Please help me with this trigonometry work!
igor_vitrenko [27]

Answer:

We have a triangle rectangle here.

We know that:

AC =  15

BC = 8

AB = 17

We know that in a triangle rectangle the longest side is the hypotenuse.

In the image we can see that the shorter side is the base, then BC is the base.

AC is the height.

AB is the hypotenuse.

Such that:

A is the top vertex.

B is the bottom right vertex

C is the bottom left vertex.

Now you need to remember the relations:

Sin(θ) = (opposite cathetus)/(hypotenuse)

Cos(θ) = (adjacent cathetus)/(hypotenuse)

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

then:

Sin (A) = (AC)/(AB) = 15/17 = 0.88

Cos(B) = (AC)/(AB) = 15/17 = 0.88

Tan(B) = (AC)/(CB) = 15/8 = 1.875

Now we want to find the measure of angle A.

We know that:

Sin(A) = 0.88

Then if we apply the Asin( ) function in both sides, we get:

Asin( Sin(A)) = Asin(0.88)

A = Asin(0.88) = 61.6°

(the Asin() function is the inverse of the sin() function)

Now we have:

sin(x) = 0.906

We do the same thing as before.

Asin(sin(x)) = Asin(0.906)

x = Asin(0.906) = 65°

And:

Sin(87°) = 0.999

3 0
3 years ago
Dylan interpreted this graph of a solution and determined that the pet store gave away 15 bones and 31 toys at a recent pet adop
Irina18 [472]

Answer:

No, he switched the values for the variables.

7 0
3 years ago
Given that f(x) = x^2? + 9x + 18 and g(x) = x + 3, find (f ÷ g) (x) and express the result in standard form.​
lawyer [7]

Answer:

x + 6

Step-by-step explanation:

(f ÷ g)(x)

= \frac{x^2+9x+18}{x+3} factorise the numerator

= \frac{(x+3)(x+6)}{x+3} ← cancel the factor (x + 3) on numerator/ denominator

= x + 6

5 0
3 years ago
Which of the following integrals represents the area of the region bounded by x = 0, x = 1 and the functions f(x) = -2x4 and g(x
leva [86]

Answer:

C. \int\limits^0_1 {-2x^4-x^2} \, dx is correct

Step-by-step explanation:

We are given that,

The region bounded by x= 0, x=1, f(x)= -2x^4, g(x)=x^2 is given in the figure below.

Now, as we have,

Area of the bounded region = \int\limits^a_b {f(x)-g(x)} \, dx,

where f(x) represents the upper curve and f(x) represents the lower curve in the bounded region.

So, as we see that,

The upper curve in the given region is f(x)= -2x^4 and the lower curve is g(x)=x^2.

Thus, the integral showing the area of the given region is,

\int\limits^0_1 {-2x^4-x^2} \, dx

Hence, option C is correct.

6 0
3 years ago
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