Here's the general formula for bacteria growth/decay problems
Af = Ai (e^kt)
where:
Af = Final amount
Ai = Initial amount
k = growth rate constant
<span>t = time
But there's another formula for a doubling problem.
</span>kt = ln(2)
So, Colby (1)
k1A = ln(2) / t
k1A = ln(2) / 2 = 0.34657 per hour.
So, Jaquan (2)
k2A = ln(2) / t
<span>k2A = ln(2) /3 = 0.23105 per hour.
</span>
We need to use the rate of Colby and Jaquan in order to get the final amount in 1 day or 24 hours.
Af1 = 50(e^0.34657(24))
Af1 = 204,800
Af2 = 204,800 = Ai2(e^0.23105(24))
<span>Af2 = 800</span>
Answer:
i would guess 3000
Step-by-step explanation:
this is because i rounded 8.50 to 10. and rounded 29886 to 30000
We know what y equals already.
y = x + 5
2x - x + 5 = -2
x + 5 = -2
-5 -5
x = -7
y = -7 + 5
y = -2
Now we have our values
Answer: (-7,-2)
or
x = -7
y = -2
Answer:
no
Step-by-step explanation:
if you do 3 x 6 x 9 that equals 162 and a right angle is 190, right?
Answer:
c ≤5
Step-by-step explanation:
less than or equal is ≤
c ≤5