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3 years ago

What is the probability of drawing either an ace or a face card, when choosing one card from the deck?

Mathematics

1 answer:

snow_lady [41]3 years ago

5 0

50: 18 jaiusbuuusbsuuuuu

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The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation.

podryga [215]

Rate of change refers to moving a certain amount of distance over a certain time period
rate of change= velocity in this case.

7 0

3 years ago

Read 2 more answers

Question is in the picture

sukhopar [10]

Answer:

bottom right 8 x 10^1

Step-by-step explanation:

multiply the numbers (2x4 is 8)

add the exponents of 10 (-3+4 is 1)

so the answer is the bottom right 8 x 10^1

7 0

3 years ago

A scooter was bought at Rs 42,000. its value depreciated at the rate of 8% per annum. find its value after one year

Alona [7]

Answer:

Rs 38,640

Step-by-step explanation:

Pay attention:

$A = P(1+r/100)^n$

The principle (p) : Rs 42,000

Rate of interest (r) : 8%

Time (n) : 1 years

Exact Amount (a) : P(1-R/100)^n

Value:

A = 42,000(1 - 8/100)^1

A = 42,000(1 - 2/25)

A = (42,000 * 23)/25

A = 1,680 * 23

A = Rs 38,640

4 0

3 years ago

HELPPP A. 9 B. 20 C. 16 D. 4

serious [3.7K]

Answer:

C 16

Step-by-step explanation:

Using ratios

3:12

12/3=4

4:x

4*4=16

x=16

4:16

hope this helps:)

6 0

3 years ago

(4) A spherical balloon is being inflated so that its diameter is increasing at a constant rate of 6 cm/min. How quickly is the

fredd [130]

In terms of its radius $r$ , the volume of the balloon is

$V(r)=\dfrac{4\pi}3r^3$

The diameter $d$ is twice the radius, so that in terms of its diameters, the balloon's volume is given by

$V(d)=\dfrac{4\pi}3\left(\dfrac d2\right)^3=\dfrac\pi6d^3$

Differentiate both sides with respect to time $t$ :

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2d^2\dfrac{\mathrm dd}{\mathrm dt}$

The diameter increases at a rate of $\frac{\mathrm dd}{\mathrm dt}=6\frac{\rm cm}{\rm min}$ . When the diameter is $d=50\,\mathrm{cm}$ , we have

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2(50\,\mathrm{cm})^2\left(6\frac{\rm cm}{\rm min}\right)=7500\pi\dfrac{\mathrm{cm}^3}{\rm min}$

or about 23,562 cc/min (where cc = cubic centimeters)

5 0

3 years ago