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Stella [2.4K]
4 years ago
10

A loudspeaker produces a musical sound by means of the oscillation of a diaphragm whose amplitude is limited to 1.9 μm.

Physics
1 answer:
Alika [10]4 years ago
8 0

Answer:

Frequency will be equal to 361.64 Hz

Explanation:

We have given amplitude A = 1.9\mu m=1.9\times 10^{-6}m

Acceleration is equal to g

Value of g=9.8m/sec^2

Acceleration is equal to a=\omega ^2A

9.8=\omega ^2\times 1.9\times 10^{-6}

\omega ^2=51.57\times 10^6

\omega =2.271\times 10^3rad/sec

Now frequency f=\frac{\omega }{2\pi }=\frac{2271}{2\times 3.14}=361.64Hz

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Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

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d_y =  \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m

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3 years ago
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4 0
3 years ago
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Answer:

Explanation:

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Answer:

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