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UkoKoshka [18]
3 years ago
14

HW 3 a : Power Supply LTspice Design a resistor/LED circuit such that the diode will be brightly let when V out i s 5 volts. Ass

ume the diode has a forward voltage of 3.65V and a forward current of 20mA, when the diode is brightly emitting light. Note: You need to round your resistors to a whole number, as you cannot purchase non - whole numbers resistors.
Physics
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

68 ohm

Explanation:

Output Voltage, Vout = 5 V

Forward voltage, Vf = 3.65 V

Forward current, If = 20 mA = 0.02 A

Let the resistance is R.

Use the formula

I_{f}=\frac{V_{out}-V_{f}}{R}

0.02=\frac{5-3.65}{R}

R = 67.5 ohm

R = 68 ohm ( approx.)

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A jet plane is flying at a constant altitude. At time t1 = 0, it has components of velocity vx = 90 m/s, vy = 110 m/s. At time t
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Answer:

a) See attachment.

b) a_avg = -8.66 i - 2.33 j

c) a = 195 degrees from + x-axis.  |a_avg| = 8.97 m/s^2

Explanation:

Given:

- Initial Velocity V_i = (90 i + 110 j)

- Final velocity V_f = (-170 i + 40 j)

- t_i = 0

- t_f = 30.0 s

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(a) Sketch the velocity vectors at t1 and t2. How do these two vectors differ?

(b) the components of the average acceleration

(c) the magnitude and direction of the average acceleration.

Solution:

- The change in velocity is given by:

                            Δ V = (V_f - V_i)

                            Δ V = ( -170 i - 90 i + 40 j - 110 j)

                            Δ V = (-260 i - 70 j)

- The change in time is given as:

                            Δ t = t_f - t_i = 30 - 0 = 30 s

-The average acceleration is:

                            a_avg = Δ V / Δ t

                            a_avg = (-260 i - 70 j) / 30

                           a_avg = -8.66 i - 2.33 j

- The magnitude of acceleration is:

                            |a_avg| = sqrt ( 8.66^2 + 2.33^2)

                            |a_avg| = sqrt (80.4245)

                            |a_avg| = 8.97 m/s^2

- The direction of acceleration is given by:

                            tan (Q) = a_y / a_x

                            Q = arctan(a_y / a_x)

                            Q = arctan(2.33 / 8.66)

                            Q = 15 degrees

Hence, 180 + 15 = a.        a = 195 degrees from + x-axis.

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