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Igoryamba
3 years ago
10

Which of the following can provide direct current?

Physics
1 answer:
Akimi4 [234]3 years ago
7 0
The answer is d) batteries

mark as brainliest if it’s helpful
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Answer:  put in neutral, apply the breaks, turn on hazards, pull off the road, last turn off the ignition.

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4 years ago
A cat lifting a barbell of 2.5 kg a distance of 3 meters. How much work is done lifting the barbell? How much work is done if th
Degger [83]

Work = (force) x (distance)

Force = weight of the barbell = (mass) x (gravity) = (2.5 kg) x (9.8 m/s²)

Work = (2.5 x 9.8 newtons) x (3 meters) = 74 newton-meters = 74 joules.

It takes 74 joules to lift the 2.5-kg load 3 meters up off the floor.

After that, as long as the load is held motionless, no more work is done.

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3 years ago
Mark creates a graphic organizer to review his notes about electrical force. Which labels belong in the regions marked X and Y?
sveta [45]

Answer:

The correct answer is A

Explanation:

The question requires as well the attached image, so please see that below.

Coulomb's Law.

The electrical force can be understood by remembering Coulomb's Law, that  describes the electrostatic force between two charged particles. If the particles have charges q_1 and q_2, are separated by a distance r and are at rest relative to each other, then its electrostatic force magnitude on particle 1 due particle 2 is given by:

|F|=k \cfrac{q_1 q_2}{r^2}

Thus if we decrease the distance by half we have

r_1 =\cfrac r2

So we get

|F|=k \cfrac{q_1 q_2}{r_1^2}

Replacing we get

|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}

We can then multiply both numerator and denominator by 4 to get

|F|=k \cfrac{4q_1 q_2}{r^2}

So we have

|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)

Thus if we decrease the distance by half we get four times the force.

Then we can replace the second condition

q_{2new} =2q_2

So we get

|F|=k \cfrac{q_1 q_{2new}}{r_1^2}

which give us

|F|=k \cfrac{q_1 2q_2}{r_1^2}\\|F|=2\left(k \cfrac{q_1 q_2}{r_1^2}\right)

Thus doubling one of the charges doubles the force.

So the answer is A.

8 0
3 years ago
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5. What is the angle between the incident and reflected rays when a ray of light incident
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Answer:

The angle will be 0 . The angle between the incident ray and the mirror is called angle of incidence while the angle between reflected ray and the normal is called angle of reflection. Here, the a ray of light is incident normally on a plane mirror.

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