Answer:
P(B/C) = 0.3333
Step-by-step explanation:
let's call B the event that a woman was wearing a belt and C the event that a woman was carrying a purse.
The probability P(B/C) that a woman was wearing a belt, given that the woman was also carrying a purse can be calculated as:
P(B/C) = P(B∩C)/P(C)
Where P(C) is the probability that a woman was carrying purse and P(B∩C) is the probability that the woman was both carrying purse and wearing belt.
So, P(C) is calculated as:
P(C) = 18 / 30 = 0.6
Because there were 30 women that walked by in an hour and of those women, 18 were carrying purses.
At the same way, P(B∩C) is equal to:
P(B∩C) = 6 / 30 = 0.2
Finally, P(B/C) is equal to:
P(B/C) = 0.2/0.6 = 0.3333
Answer:
the correct graph is b for this problem
The company lost a little less than $100.
Since the number is negative, we know that they lost money. If it was positive, it would've indicated they made money. If they made no money, they would've broken even. This narrows it down to the last two. Since 98 < 100, we know they lost less than $100, which leaves us with the last one.
You did everything right. You leave "t" by itself because you don't have a given time frame. But I'll say you used the correct formula and showed your work well.
