Question

The number of cars sold by a car salesperson during each of the last 25 weeks is the following: Number Sold Frequency 0 10 1 10 2 5 What is the probability that the salesperson will sell one car during a week

Answer 1

Answer:

μ=0.8

Step-by-step explanation:

The expected value of X is calculated as E(X) = μ = ∑xi P(X = xi)

Given the table below

Sold(x)____0____ 1.____2

Freq(X)____10___ 10____5

E(X) = μ = ∑xi P(X = xi)

Total outcome is 10+10+5=25

Then, probability of each car sold is

P(0) =10/25

P(1) =10/25

P(2) =5/25

The corresponding probabilities are 10/25, 10/25 and 5/25. Thus, the expected value of X equals

μ = x1•P(X=0) + x2•P(X=1) + x3•P(X=2)

μ = 0(10/25) + 1(10/25) + 2(5/25)

μ = 0 + 0.4 + 0.4

μ = 0.8

Thus, the expected value the person will sell one car is 0.8