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Valentin [98]
2 years ago
9

I need answers asap. ​

Mathematics
1 answer:
Greeley [361]2 years ago
8 0
J. The wonderful answer is J
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Solve for y 3x+11y=-5
mars1129 [50]
\displaystyle 3x+11y=-5\quad\Big| -3x\\\\11y=-5-3x\quad\Big|:11\\\\y= -\frac{5+3x}{11}
6 0
3 years ago
What is the solution set of equation ?
Vanyuwa [196]

Answer:

Option 4

Step-by-step explanation:

You divide 1/2 by the whole problem

5x-15=20

and go from there its too long to explain but its option 4

3 0
3 years ago
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0
3 years ago
Heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelp
Tema [17]

Answer:

1. not possible, 2. a. 65 b. 115  c.115

Step-by-step explanation:

def. sup. <

vertical angles post.

corresponding angles thm.

4 0
3 years ago
Read 2 more answers
A portion of an amusement park ride is shown. Find EF. Write your answer as a fraction in the simplest form
netineya [11]

Answer: I CAME IN LIKE A BUTTERBALL!

Step-by-step explanation: I NEVER HIT SO HARD BEFORE!!!!!!!!!!!!!!!!!!!!!!

4 0
2 years ago
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