I need answers asap.

Olegator [25]

Answer:

Just read the step by step

Step-by-step explanation:

Ok so what you want to do this split the numbers up into sections for example 15-20 find numbers through those numbers. Then count how many there are. After putting them in the blank space and the use the graph to put the same number in. Hope this helps!

7 0

2 years ago

Jamie has 4 apples and 6 bananas. Each apple cost 0.75 and each banana cost 0.6” write an expression representing the total cost

Lorico [155]

(0.75*4) + (0.6*6) = 6.6

answer: 6.6

5 0

3 years ago

Read 2 more answers

A car traveling east at 40.0 m/s passes a trooper hiding at the roadside. The driver uniformly reduces his speed to 25.0 m/s in

Anni [7]

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 40 m/s

Final speed of the car, v = 25 m/s

Time taken, t = 3.5 s

(a) We need to find the magnitude and direction of the car’s acceleration as it slows down. It can be calculated using formula as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{25-40}{3.5}$

$a=-4.28\ m/s^2$

The acceleration is in the opposite direction of motion i.e. west.

(b) Let s is the distance the car travel in the 3.5-s time period. It can be calculated using the third equation of motion as

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{25^2-40^2}{2\times (-4.28)}$

s = 113.9 meters

Hence, this is the required solution.

6 0

4 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$