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Lubov Fominskaja [6]
2 years ago
5

Ivan and Tanya share £150 in the ratio 4 : 1 Work out how much more Ivan gets compared to Tanya.

Mathematics
1 answer:
Serhud [2]2 years ago
4 0

Answer:

£90 more

Step-by-step explanation:

4+1=5

150/5=30

I:T

4:1 ×30

120:30

120-30=90

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What is 1035 divided by 88
konstantin123 [22]

Answer:

11.7613636364

Step-by-step explanation:

or just round up to 12

6 0
3 years ago
Read 2 more answers
Maria and victor each play a video game. The ratio of the number of points Maria scores to the number of points victor scores is
zvonat [6]

Answer:

Step-by-step explanation:

I don't know what a tape diagram is but I can give you the equation and the answer.

Let Victor have x points

Let Maria have y points

y = x + 424

y/x = 5/3                     Cross multiply

3y = 5x                       Divide by 3

y = 5x/3                      I Could have just multiplied by x

y = x + 424

5x/3 = x + 424           Multiply both sides by 3

5x = 3x + 1272           Subtract 3x from both sides.

5x-3x = 1272              Combine the left.

2x = 1272                    Divide by 2

2x/2 = 1272/2

x = 636

Victor Scored 636 points

Maria Scored 636 + 424 = 1060

7 0
2 years ago
If A, B, and C are collinear, and AB = 18, AC = 41, what is a possible measure of BC?
ikadub [295]

Step-by-step explanation:

As ANC are collinear,

AB+BC=AC

so,

18+BC = 41

BC = 41-18

BC = 23 is the answer.

8 0
3 years ago
Read 2 more answers
A psychologist would like to examine the effect of fatigue on mental alertness. An attention test is prepared which requires sub
lianna [129]

Answer:

The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that  fatigue does not significantly increase errors on an attention task at 0.05 significance level

Step-by-step explanation:

We formulate null and alternate hypotheses are

H0 : u1 < u2 against Ha: u1 ≥ u 2

Where u1 is the group tested after they were awake for 24 hours.

The Significance level alpha is chosen to be ∝ = 0.05

The critical region t ≥ t (0.05, 13) = 1.77

Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13

Here the difference between the sample means is x`1- x`2= 35-24= 11

The pooled estimate for the common variance σ² is

Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]

= 1/13 [ 120²+360²]

Sp = 105.25

The test statistic is

t = (x`1- x` ) /. Sp √1/n1 + 1/n2

t=   11/ 105.25 √1/5+ 1/10

t=  11/57.65

t= 0.1908

The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that  fatigue does not significantly increase errors on an attention task at 0.05 significance level

5 0
3 years ago
the combined age of april and laura is 23 years. laura's age is two years more than half of april's age. what is laura's age
Kipish [7]

Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = \frac{x}{2}

2 years more than half of April's age = \frac{x}{2}+2

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$\Rightarrow \ \ x+(\frac{x}{2}+2) =23

$\Rightarrow \ \ x+\frac{x}{2}+2 =23

$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

$\Rightarrow \ \ \frac{x\times2}{1\times2}+\frac{x}{2}+\frac{2\times2}{1\times2} =23

$\Rightarrow \ \ \frac{2x}{2}+\frac{x}{2}+\frac{4}{2} =23

Denominators are same, now add the fractions.

$\Rightarrow \ \ \frac{2x+x+4}{2} =23

Do cross multiplication.

$\Rightarrow \ \ 2x+x+4=23\times2

$\Rightarrow \ \ 3x=46-4

$\Rightarrow \ \ 3x=42

$\Rightarrow \ \ x=14

Aprils's age = 14 years

Laura's age = \frac{14}{2}+2

                    = 7 + 2

Laura's age = 9

Hence Laura's age is 9 years.

8 0
3 years ago
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