The length of a rectangle is 4 cm less than twice the width. express as an integer the maximum width of the rectangle when the perimeter is less than 78 cm.
Answer:
a² + 2ab + b²
Explanation:
⇒ (a + b)²
⇒ (a + b)(a + b)
[apply distributive method: (a + b) (c + d) = ac + ad + bc + bd]
⇒ a² + ab + ab + b²
⇒ a² + 2ab + b²
19.6666667 is what i calculated:)
Answer:
First one A and D
Second A and C
Third A and D
Fourth 20 / 4 = X
X = 5
Step-by-step explanation:
