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shepuryov [24]
3 years ago
8

Actual Distance Map Distance Part of Scale Answer 3. Violetsville to Forkcity is 50 miles 10 in. 1 in. = ?

Mathematics
1 answer:
Rudik [331]3 years ago
4 0
The answer would be 5 miles for 1 inch
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Please help 6th grade math please please help
tiny-mole [99]

Answer:

Least Value: 16

Median: 26

Upper Quartile: 30

Lower Quartile: 20

Greatest Value: 34

Interquartile Range: 10

Range: 18

6 0
3 years ago
Construct a circle graph that represents the following data concerning the monthly expenses for a family budget.
rodikova [14]

Answer:

The circle graph is attached.

Step-by-step explanation:

a) Data and Calculations:

Monthly Expenses for a Family Budget

Expenses   Percentage   Degree

Housing            35%        130°  (360° * 35%)

Food                  14%         50°  (360° * 14%)

Clothing            17%          60°  (360° * 17%)

Entertainment  12%          40°  (360° * 12%)

Auto                22%           80°  (360° * 22%)

b) The result shows that Housing expense took more than one-third of the circle with auto expenses occupying the next biggest chunk of the circle.  Clothing came third to occupy one-sixth of the circle, with food and entertainment trailing behind with less than one-sixth of the circle respectively.

Download xlsx
6 0
3 years ago
Whats the answer to this question ?
Andrei [34K]
6 3/7 multiplied by 21 is 135. Your answer is C. 135 <span />
5 0
3 years ago
Read 2 more answers
Two equations are given below: m + 4n = 8 m = n - 2 What is the Solution ?
Sophie [7]
M+4n=8
m=n-2
we see that m=n-2
so we can subsitute 'n-2' for m in the first equation
(n-2)+4n=8
n-2+4n=8
5n-2=8
add 2 to both sides
5n=10
divide by 5
n=2
subsitute
n=2
m=n-2
m=2-2
m=0

m=0
n=2

the answer is c. 0,2
7 0
3 years ago
6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A
Alexxx [7]

Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

42 + 0.72m = 70 + 0.12m

Collect like terms

0.72m - 0.12m = 70 - 42

0.6m = 28

Divide both sides by 0.6

\frac{0.6m}{0.6} = \frac{28}{0.6}

m = 46.7

At approximately 47 miles, both trucks would cost the same amount.

Check:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Plug in the value of x = 47

= 42 + 0.72(47) = $75.84 ≈ $76

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Plug in the value of x = 47

= 70 + 0.12(47) = $75.64 ≈ $76

7 0
3 years ago
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