All categories

3 years ago

Does this system of equations have one solution, no solutions, or an infinite number of solutions?

Mathematics

1 answer:

sertanlavr [38]3 years ago

8 0

Y=2x+5

2(2x+5)+4x=10

4x+10+4x=10

8x=20

So there's one solution, x=2.5

You might be interested in

Hello! Could y’all please explain why this is Decay and not growth?

svetlana [45]

Answer:

This is an Exponential Decay

Step-by-step explanation:

A = 1200(0.85)⁶

The above expression is an Exponential Decay because 0.85 is less than 1

The formula for Exponential Decay

= y = a (1 - r)^t

We equate both equation together

Where

a = 1200

1 - r = 0.85

t = 6

Solving for r

1 - r = 0.85

r = 1 - 0.85

r = 0.15

Converting to Percentage

r = 15% decay rate

3 0

3 years ago

Please help me with this.

OLga [1]

Swapping rows alters the sign of the determinant:

$\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}$

Multiplying a single row by a scalar scales the determinant by the same amount:

$\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}$

Then

$\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}$

8 0

1 year ago

Find the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6.

DENIUS [597]

We have that the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6. is

$m=\infty$

From the question we are told

Find the slope of the line containing the pair of points f(1) = -6 and f(-7) = -6.

Where Standard form of Equation is

y=mx+c

Generally the equation for the Slope is mathematically given as

$m=\frac{y_2-y_1}{x_2-x_1}$

Therefore

$m=\frac{-7-1}{-6-(-6)}\\\\ m= \infty$

Therefore

The slope of this line is

$m=\infty$

For more information on this visit

brainly.com/question/23366835

7 0

1 year ago

What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D

Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

$\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a} \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a} = \frac{-6-14}{2}=\frac{-20}{2} = -10$

4 0

3 years ago

Can someone please answer i will mark brainliest

Dmitrij [34]

A) 2007
b) 120
c) the donations are decreasing as years increase

7 0

2 years ago

Read 2 more answers