Answer:
Step-by-step explanation:
In this particular case we have the following system of equations:
y
=
−
3
x
+
4
[
E
q
.
1
]
x
+
4
y
=
−
6
[
E
q
.
2
]
Substituting
[
E
q
.
1
]
in
[
E
q
.
2
]
:
x
+
4
(
−
3
x
+
4
)
=
−
6
Applying the distributive property on the left side:
x
−
12
x
+
16
=
−
6
Simplifying
:
−
11
x
=
−
22
Solving for
y
:
x
=
−
22
−
11
=
2
Substituting
x
=
2
in
[
E
q
.
1
]
:
y
=
−
3
(
2
)
+
4
=
−
2
Therefore
, the solutions are
x
=
2
and
y
=
−
2
Answer:
23°
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)
Answer:
![b\sqrt[n]{a}](https://tex.z-dn.net/?f=b%5Csqrt%5Bn%5D%7Ba%7D)
Step-by-step explanation:
High school math tip: learn how to apply the ratios 1:1:√2 for the 45/45/90 right triangle and 1:√3:2 for the 30/60/90 triangle; these two triangles probably constitute 90% of the examples and problems you'll see.
He we have half a square, the 45/45/90 isosceles right triangle, sides in ratio 1:1:√2. We write that ratio for our sides and solve.
1:1:√2 = (3/2)√2 : y : x
Ratios are pretty much like fractions, and we can make fraction equations out of corresponding pairs:
1/1 = ( (3/2)√2 ) / y
y = (3/2)√2
1 /√2 = (3/2)√2 / x
x = (3/2)√2 × √2 = (3/2)(2) = 3
Answer: y = (3/2)√2, x = 3
It's not too hard to get fast at these and just say y=(3/2)√2 because it's an isosceles triangle and x = y×√2 = 3 for the hypotenise.
