Answer:
C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
from the question ,
M = 0.250M
V = 3.00 L
M = n / V
n = M * v
n = 0.250M * 3.00 L = 0.75 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
n = 0.75 mol NaOH
m = molecular mass of NaOH = 40 g/mol
n = w / m
w = n * m
w = 0.75 mol * 40 g/mol = 30.0 g
Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .
The heat absorbed to raise temperature : Q = 31350 J
<h3>Further explanation
</h3>
Given
m = mass = 150 g
Δt = Temperature difference : 50 °C
Required
Heat absorbed
Solution
Heat can be formulated
<em>
Q = m.c.Δt
</em>
The specific heat of water = c = 4.18 J/g °C
Input the value :
Q = 150 x 4.18 x 50
Q = 31350 J
I think the answer is
A) an acid
Monosaccharide are
any of the class of sugars (e.g., glucose) that cannot be hydrolyzed to give a simpler sugar.
examples: fructose ,galactose glucose
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, for 0.904 g of precipitate, that is lead (II) iodide, we can compute the initial moles of lead (II) ions in lead (II) nitrate:
Finally, the resulting molarity in 30.8 mL (0.0308 L):
Regards.
