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SVEN [57.7K]
2 years ago
5

Which property of water contributes most to the ability of fish in lakes to survive very cold winters?.

Chemistry
1 answer:
Valentin [98]2 years ago
6 0

Answer:

And that means fish must be able to survive down here. This is due to a special property of water: the elasticity of H2O. We know that when the temperature sinks below freezing, water first contracts and then expands as it begins to turn to ice. Ice, being lighter than water, floats.

Explanation:

The property of water that allows fish to survive in a lake that is frozen over is the fact that ice is less dense than liquid water.

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A student prepares a model of multicellular organisms which statement best explains the difference between tissues and organs an
olga_2 [115]

Answer:

C.)organs are a group of two or more different types of tissues that work together to perform a specific function

Explanation:

Cells of similar function are grouped together into tissues. For example, cardiac muscle tissue is present only in the heart, and made up of specialised cells called cardiomyocytes, or cardiac muscle cells. These cells contract to pump blood around the body.

The heart is an organ, consisting of multiple types of tissue including cardiac muscle tissue, connective tissue, blood vessels and epithelial tissue. Therefore, organs represent a group of at least two types of tissue that work together to carry out functions in the body.

7 0
3 years ago
What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure =  1.1 atm

and V is the volume = 14.5 L 

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

       = 0.68 moles SO2

∴ moles CaSO3 = 0.68 moles

so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol


∴ mass = 0.68 moles* 120 g/mol = 81.6 g
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