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Answer:
1.64x10⁻¹⁸ J
Explanation:
By the Bohr model, the electrons surround the nucleus of the atom in shells or levels of energy. Each one has it's energy, and the electron doesn't fall to the nucleus because it can reach another level of energy, and then return to its level.
When the electrons go to another level, it absorbs energy, and then, when return, this energy is released, as a photon (generally as luminous energy). The value of the energy can be calculated by:
E = hc/λ
Where h is the Planck constant (6.626x10⁻³⁴ J.s), c is the light speed (3.00x10⁸ m/s), and λ is the wavelength of the photon.
The wavelength can be calculated by:
1/λ = R*(1/nf² - 1/ni²)
Where R is the Rydberg constant (1.097x10⁷ m⁻¹), nf is the final orbit, and ni the initial orbit. So:
1/λ = 1.097x10⁷ *(1/1² - 1/2²)
1/λ = 8.227x10⁶
λ = 1.215x10⁻⁷ m
So, the energy is:
E = (6.626x10⁻³⁴ * 3.00x10⁸)/(1.215x10⁻⁷)
E = 1.64x10⁻¹⁸ J
Answer: 3.68 x 10^21 particles
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
Since 1 mole is the same as molar mass of a substance
237 g = 6.02 x 10^23 atoms
1.45g = Z atoms
To get the value of Z, cross multiply:
(Z atoms x 237g) = (6.02 x 10^23 atoms x 1.45g)
237Z = 8.729 x 10^23
Z = (8.729 x 10^23 / 237)
Z = 3.68 x 10^21
Thus, there are 3.68 x 10^21 representative particles in 1.45 g of the molecular compound.
Answer:
1.19 g
Explanation:
Given that:
Molecular weight of diene 136 g/mol
Molecular weight of Maleic Anhydride 96 g/mol
Mass of crude diene = 2.5 g
Percent of Composition for Peak A = 66%
Percent of Composition for Peak B = 22.66%
Percent of Composition for Peak C = 11.33%
Let us determine the amount of diene in the sample;
So, using to represent the amount of diene; we have :
=
=
= 1.65 g
Using the limiting reagent equation to determine the amount of Maleic Anhydride
=
=
= 1.19 g
The grams of Maleic Anhydride used to react with 2.5 g sample of crude diene = 1.19 g
Answer:
can only accommodate 2 electrons