Answer:
The number of customers needed to break even is

Step-by-step explanation:
Rent per month = $ 7200
Rent per year, $ 
= $ 86400 -------------(1)
Insurance per year = $ 4200 ---------(2)
Total direct cost for 2 servers (withoout tax) per year,
= $ 
= $ 60000
Total cost for helper ( without tax) per year,
= $ 
= $ 15000
Total cost for employees per year (without tax),
= $ (60000 +15000) = $ 75000
Total cost per year for employees including tax,
$ 
= $ 
= $ 80737.5 -----------------------(3)
So,
total cost for running the restaurant (except food)
= (1) + (2) + (3) = $ 
= $ 171337.5
Average total profit per customer,
= ( Average per customer payment - average cost of food per customer)
= $ (45.47 - 20.18)
= $ 25.29
So, total number of customer needed to break even,
= 
\simeq 6775
One way to solve this problem is by:
First multiply both sides by 10
30r=9
Now divide by 30
r=0.3 Final Answer
I gotten this question before the answer is 3
<h3>
Answer: B) Only the first equation is an identity</h3>
========================
I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
---------------------------------
Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.