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lutik1710 [3]
2 years ago
6

I REALLY NEED HELP!!! 5^-3=

Mathematics
2 answers:
Readme [11.4K]2 years ago
7 0

Answer:

\frac{1}{125}

Step-by-step explanation:

whenever you see a negative exponenet, you should always write the reciprocal of it

5^{-3} becomes  \frac{1}{5^{3} }

solve the denominator

5^{3} = 125

therefore, your answer is \frac{1}{125}

hope this helps!! :)

stiv31 [10]2 years ago
3 0
1/125 or 0.008
fraction or decimal
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540/2 = 270

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Whats the lowest common multiple of 120 and 19600​
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Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

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Solve for x. 5(x – 10) = 30 – 15x
SIZIF [17.4K]
Hey!


The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

<em>Original Equation :</em>
5 ( x - 10 ) = 30 - 15x

<em>New Equation {Changed by Distribution} :</em>
5x - 50 = 30 - 15x

The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

<em>Old Equation :</em>
5x - 50 = 30 - 15x

<em>New Equation {Changed by Adding 50 to Both Sides} :</em>
5x = 80 - 15x

And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.

<em>Old Equation :</em>
5x = 80 - 15x

<em>New Equation {Changed by Adding 15x to Both Sides} :</em>
20x = 80

Now we divide both sides by 20 to get x on it's own.

<em>Old Equation :</em>
20x = 80

<em>New Equation {Changed by Dividing Both Sides by 20} :</em>
\frac{20x}{20} = \frac{80}{20}

Finally, all we have to do is solve to find x.

<em>Old Equation :</em>
\frac{20x}{20} = \frac{80}{20}

<em>Solution {Old Equation Solved} :</em>
x = 4

<em>So, in the equation </em><span><em>5 ( x – 10 ) = 30 – 15x</em>,  x = 4.

Hope this helps!


- Lindsey Frazier ♥</span>
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2 years ago
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