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lys-0071 [83]
3 years ago
8

Determine which situation could be represented by the system of linear equations given below

Mathematics
1 answer:
Rudiy273 years ago
7 0
The answer is
56x-(23y)^9/3 = 42
dingling44
2 years ago
thats not even a answer????
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Please help me I don’t know how to solve it and will mark brainiliest
Sindrei [870]

Answer: One plain roll is 4 dollars and one shiny roll is 6 dollars.

Step-by-step explanation:

lets start by saying

rolls of plain wrapping paper = x

rolls of shiny wrapping paper = y

Kathryn sold 4 plain rolls and 3 shiny rolls for 34 dollars.

4x+3y=34

Eugene sold 4 plain rolls and 2 shiny rolls for 28 dollars

4x+2y=28

Both equations will look like this.

4x+3y=34

-1(4x+2y)=(28)-1

we can multiply the second equation by -1 to get y alone. (doesn't matter which equation). Once you do that, the positive 4x and the negative 4x cancel out, 3y-2y=1y and 34-28=6. you are left with

1y=6 so one shiny roll is 6 dollars.

now use that price to find the cost of the plain roll.

lets use Kathryn's equation

4x + 3(6)=34

4x + 18= 34

      -18  -18

4x=16. Divide by 4 to find cost of one plain roll.

16÷4=4. One plain roll costs 4 dollars.

Lets check. Using Kathryn's equation,

4(4) + 3(6)=34

16+18=34

34=34. We are right.

3 0
3 years ago
- En la siguiente sucesión de números 13, 8, 3, -2, -7, -12, -17… ¿Cuál es la regla algebraica para obtener la sucesión?
melomori [17]
I don’t understand Spanish
6 0
3 years ago
Write an equation in point-slope form of a line that has a slope of 2/3 and
Serggg [28]

Answer:

y= 2/3x -1

Step-by-step explanation:

Ok so basically we want to put it in the form y=mx+b where m is 2/3 and passes through the point (9,5). So sub in the x and y of the point in brackets into the equation. 5= 2/3(9) + b and solve for b so b = -1. Therefore the equation is y=2/3x -1

5 0
3 years ago
Use mathematical induction to show that 4^n ≡ 3n+1 (mod 9) for all n equal to or greater than 0
cestrela7 [59]
When n=0, you have

4^0=1\equiv3(0)+1=1\mod9

Now assume this is true for n=k, i.e.

4^k\equiv3k+1\mod9

and under this hypothesis show that it's also true for n=k+1. You have

4^k\equiv3k+1\mod9
4\equiv4\mod9
\implies 4\times4^k\equiv4(3k+1)\mod9
\implies 4^{k+1}\equiv12k+4\mod9

In other words, there exists M such that

4^{k+1}=9M+12k+4

Rewriting, you have

4^{k+1}=9M+9k+3k+4
4^{k+1}=9(M+k)+3k+3+1
4^{k+1}=9(M+k)+3(k+1)+1

and this is equivalent to 3(k+1)+1 modulo 9, as desired.

3 0
4 years ago
Neeed helpppp asppp I ready math
nikitadnepr [17]

Answer:

D because we just distribute the 0.5

Hope this helps and brainliest please

6 0
3 years ago
Read 2 more answers
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